下拉菜单不显示子菜单

Question

以下是我的下拉按钮的代码，其中包含1个额外级别。

当我点击按钮时，它工作正常，但是当我尝试在子菜单的下拉列表中单击时，我意识到出现了错误，我的四个项目只显示了最后一个子菜单。

＆＃13;

＆＃13;

.icon-cadet-left {
  float: right;
}
.dropbtn {
  width: 300px;
  background-color: #4CAF50;
  color: white;
  padding: 16px;
  font-family: 'Play';
  font-size: 20px;
  border: none;
  cursor: pointer;
  text-transform: uppercase;
  letter-spacing: 2px;
}
.dropdown {
  position: relative;
  display: inline-block;
}
.dropdown-content {
  display: none;
  position: relative;
  background-color: #f9f9f9;
  min-width: 160px;
  box-shadow: 0px 8px 16px 0px rgba(0, 0, 0, 0.2);
}
.dropdown-content a {
  width: 300px;
  color: black;
  font-family: 'Play';
  letter-spacing: 2px;
  padding: 12px 16px;
  text-decoration: none !important;
  display: block;
  text-align: center;
  border-bottom: 0.1em solid #e1e1e1;
  border-radius: 5%;
  text-transform: uppercase;
  overflow: hidden;
}
#dropdown-submenu {
  display: none;
  background-color: #f9f9f9;
  position: absolute;
  box-shadow: 0px 8px 16px 0px rgba(0, 0, 0, 0.2);
  left: 100%;
  top: 0px;
}
#dropdown-submenu a {
  z-index: 1000;
  width: 300px;
  color: black;
  font-family: 'Play';
  letter-spacing: 2px;
  padding: 12px 16px;
  text-decoration: none !important;
  display: block;
  text-align: center;
  border-bottom: 0.1em solid #e1e1e1;
  border-radius: 5%;
  text-transform: uppercase;
}
.dropdown-content a:hover {
  background-color: #f1f1f1
}
#dropdown-submenu a:hover {
  background-color: #f1f1f1
}
.dropdown:hover .dropdown-content {
  display: block;
}
.dropdown-content:hover #dropdown-submenu {
  display: block;
}
.dropdown:hover .dropbtn {
  background-color: #3e8e41;
}

＆＃13;

<div class="pricing-button">
  <div class="dropdown">
    <button class="dropbtn">Logo Design</button>
    <div class="dropdown-content animated fadeIn">
      <a class="span1" href="#">Logo & Identity<i class="fa fa-caret-right icon-cadet-left"></i></a>
      <div id="dropdown-submenu">
        <a>Logo Design</a>
        <a>Business Cards</a>
        <a>Sationary</a>
        <a>Holiday Doodles</a>
      </div>
      <a class="hover2" href="#">Business & Advertising<i class="fa fa-caret-right icon-cadet-left"></i></a>
      <div id="dropdown-submenu">
        <a>Sample 01</a>
        <a>Sample 02</a>
        <a>Sample 03</a>
        <a>Sample 04</a>
      </div>
      <a class="hover3" href="#">Website & Digitals<i class="fa fa-caret-right icon-cadet-left"></i></a>
      <div id="dropdown-submenu">
        <a>Sample 01</a>
        <a>Sample 02</a>
        <a>Sample 03</a>
        <a>Sample 04</a>
      </div>
      <a class="hover4" href="#">Textile Designing<i class="fa fa-caret-right icon-cadet-left"></i></a>
      <div id="dropdown-submenu">
        <a>Sample 01</a>
        <a>Sample 02</a>
        <a>Sample 03</a>
        <a>Sample 04</a>
      </div>
    </div>
  </div>
</div>

＆＃13;

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Answer 1

所以这就是我在代码中改变的内容：

1. 您的语法无效 - 您无法使用多个id s-使用class。

   所以我将dropdown-submenu更改为class。

2. 而不是.dropdown-content:hover #dropdown-submenu使用此：

   .dropdown-content a:hover + .dropdown-submenu {
       display: block;
   }
   

   相邻的兄弟选择器（+）选择紧跟菜单dropdown-submenu标记后的a。

  

相邻的兄弟选择器（+），用于选择紧随其后的兄弟元素。   有关示例，请参阅here和here。

让我知道您对此的反馈。谢谢！

＆＃13;
＆＃13;
.icon-cadet-left {
  float: right;
}
.dropbtn {
  width: 300px;
  background-color: #4CAF50;
  color: white;
  padding: 16px;
  font-family: 'Play';
  font-size: 20px;
  border: none;
  cursor: pointer;
  text-transform: uppercase;
  letter-spacing: 2px;
}
.dropdown {
  position: relative;
  display: inline-block;
}
.dropdown-content {
  display: none;
  position: relative;
  background-color: #f9f9f9;
  min-width: 160px;
  box-shadow: 0px 8px 16px 0px rgba(0, 0, 0, 0.2);
}
.dropdown-content a {
  width: 300px;
  color: black;
  font-family: 'Play';
  letter-spacing: 2px;
  padding: 12px 16px;
  text-decoration: none !important;
  display: block;
  text-align: center;
  border-bottom: 0.1em solid #e1e1e1;
  border-radius: 5%;
  text-transform: uppercase;
  overflow: hidden;
}
.dropdown-submenu {
  display: none;
  background-color: #f9f9f9;
  position: absolute;
  box-shadow: 0px 8px 16px 0px rgba(0, 0, 0, 0.2);
  left: 100%;
  top: 0px;
}
.dropdown-submenu a {
  z-index: 1000;
  width: 300px;
  color: black;
  font-family: 'Play';
  letter-spacing: 2px;
  padding: 12px 16px;
  text-decoration: none !important;
  display: block;
  text-align: center;
  border-bottom: 0.1em solid #e1e1e1;
  border-radius: 5%;
  text-transform: uppercase;
}
.dropdown-content a:hover {
  background-color: #f1f1f1
}
.dropdown-submenu a:hover {
  background-color: #f1f1f1
}
.dropdown:hover .dropdown-content {
  display: block;
}
.dropdown-content a:hover + .dropdown-submenu {
  display: block;
}
.dropdown:hover .dropbtn {
  background-color: #3e8e41;
}
＆＃13;
<div class="pricing-button">
  <div class="dropdown">
    <button class="dropbtn">Logo Design</button>
    <div class="dropdown-content animated fadeIn">
      <a class="span1" href="#">Logo & Identity<i class="fa fa-caret-right icon-cadet-left"></i></a>
      <div class="dropdown-submenu">
        <a>Logo Design</a>
        <a>Business Cards</a>
        <a>Sationary</a>
        <a>Holiday Doodles</a>
      </div>
      <a class="hover2" href="#">Business & Advertising<i class="fa fa-caret-right icon-cadet-left"></i></a>
      <div class="dropdown-submenu">
        <a>Sample 01</a>
        <a>Sample 02</a>
        <a>Sample 03</a>
        <a>Sample 04</a>
      </div>
      <a class="hover3" href="#">Website & Digitals<i class="fa fa-caret-right icon-cadet-left"></i></a>
      <div class="dropdown-submenu">
        <a>Sample 01</a>
        <a>Sample 02</a>
        <a>Sample 03</a>
        <a>Sample 04</a>
      </div>
      <a class="hover4" href="#">Textile Designing<i class="fa fa-caret-right icon-cadet-left"></i></a>
      <div class="dropdown-submenu">
        <a>Sample 01</a>
        <a>Sample 02</a>
        <a>Sample 03</a>
        <a>Sample 04</a>
      </div>
    </div>
  </div>
</div>
＆＃13;
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Answer 2

我看到你的代码有相同的id =＆＃34; dropdown-submenu＆＃34;好几次，但那不应该。 id属性指定HTML元素的唯一ID（该值在HTML文档中必须是唯一的）。如果您需要多次，那么您应该声明为class =＆＃34; dropdown-submenu＆＃34;然后你必须使用.dropdown-submenu而不是#dropdown-submenu。

请首先纠正您的ID相关错误，然后尝试。希望它应该有用。

谢谢！