Question

我想知道是否可以在c＃中实现与下面代码类似的签名：

public abstract class baseClass
{
    public abstract float function(derivedType a, derivedType b);
}

public class derived: baseClass
{
    public override float function(derived a, derived b)
    {
        return something to do with a and b;
    }
}

希望我能清楚地知道我要做些什么，欢呼。

编辑：我尝试了以下但没有成功，希望它也可以澄清我尝试做的事情：

public abstract class baseClass
{
    public abstract float function<T>(T a, T b) where T:baseClass;
}

public class derived: baseClass
{
    public override float function<derived>(derived a, derived b)
    {
        return a.value + b.value;
    }

    public float value;
}

显然，派生的内容并未包含＆＃39; value＆＃39;的定义。据视觉工作室说。

编辑，解决方案：

public abstract class baseClass<T> where T: baseClass<T>
{
    public abstract float function(T a, T b);
}

public class derived : baseClass<derived>
{
    public override float function(derived a, derived b)
    {
        return a.value + b.value;
    }

    public float value;
}

感谢大家的帮助：）

Answer 1

如果我理解你正在寻找什么，你所要做的就是：

public abstract class baseClass<T> where T : baseClass<T>
{
    public abstract float Foo(T a, T b);
}

public class derived : baseClass<derived>
{
    public override float Foo(derived a, derived b)
    {
        throw new NotImplementedException();
    }

    public float value;
}

将派生类型作为参数传递给抽象类

1 个答案: