Question

我正在制作一个程序，该程序从用户那里获取一个短语，然后对元音进行计数，然后根据计数按升序排列显示所有元音。

它的外观示例：

Welcome to the vowel counter and sorter! 
Enter a phrase!

aaaaaeeeeiiioou

The vowels and their count:

u 1 

o 2 

i 3 

e 4 

a 5

我认为我的代码很好，除非我真的不知道在＆＃34之后要做什么;元音和它们的数量是：在我对元音和计数进行排序之后

    int[] vCount = new int[5];

    System.out.println("Welcome to the vowel counter and sorter!\nEnter a phrase!");
    String input = keyboard.nextLine();

    String upInput = input.toUpperCase();

    //examine all characters

    for (int i=0; i<upInput.length(); i++)
    {
        switch (upInput.charAt(i))
        {
            case 'A':
                vCount[0]++;
                break;
            case 'E':
                vCount[1]++;
                break;
            case 'I':
                vCount[2]++;
                break;
            case 'O':
                vCount[3]++;
                break;
            case 'U':
                vCount[4]++;
                break;
        }
    }

    char[] vArray = {'A', 'E', 'I', 'O', 'U'};
    //Bubble Sort
    boolean hasSwapped = true;

    while (hasSwapped == true)
    {
        hasSwapped = false; //Assumes it is sorted

        for (int i = 0; i<vCount.length-1; i++)
        {
        if (vCount[i] > vCount[i+1])
        {
            int temp = vCount[i];
            vCount[i] = vCount[i+1];
            vCount[i+1] = temp;
            hasSwapped = true;
            char temp2 = vArray[i];
            vArray[i] = vArray[i+1];
            vCount[i+1] = temp2;
        }
        }
    }
    System.out.println("The vowels and their count:");
    for (int i=0; i<vArray.length; i++)
    {
        System.out.println(vArray[i]+ " " +vCount[i]);
    }
}

我的输出完全错误并搞砸了。我假设您需要一个for循环来打印数组，但我的输出是关闭的：

Enter a phrase!


aaaaaeeeeiiioou

The vowels and their count:

U 1


U 79


U 79


U 79

U 79

请帮我正确打印？

Answer 1

在您的排序代码中查看我的评论：

    if (vCount[i] > vCount[i+1])
    {
        int temp = vCount[i];
        vCount[i] = vCount[i+1];
        vCount[i+1] = temp;
        hasSwapped = true;
        char temp2 = vArray[i];
        vArray[i] = vArray[i+1];
        vCount[i+1] = temp2; // this line is wrong. reference vArray not vCount
    }

作为一个注释，这样的问题是你不应该自己重写排序的原因。有图书馆。使用char到int的映射来实现它会更加清晰，只需根据最高计数输出结果。但是，以下内容应该可以解决您的问题：

    if (vCount[i] > vCount[i+1])
    {
        int temp = vCount[i];
        vCount[i] = vCount[i+1];
        vCount[i+1] = temp;
        hasSwapped = true;
        char temp2 = vArray[i];
        vArray[i] = vArray[i+1];
        vArray[i+1] = temp2;
    }

排序后输出？

1 个答案: