同时引用两个模型

Question

我有一张预订表，指向在room_bookings或restaurant_bookings表上预订的房间或餐厅桌面的迁移

售票：

Schema::create('bookings', function (Blueprint $table) {
        $table->increments('id'); 
        $table->morphs('booking');
        $table->morphs('business');
        $table->boolean('status');
}

room_bookings：

Schema::create('room_bookings', function (Blueprint $table) {
            $table->increments('id'); 
            $table->string('from');
            $table->string('to');
}

restaurant_bookings：

Schema::create('restaurant_bookings', function (Blueprint $table) {
            $table->increments('id'); 
            $table->string('table_no');
}

餐厅：

Schema::create('restaurants', function (Blueprint $table) {
        $table->increments('id'); 
        $table->string('name');
}

间：

Schema::create('rooms', function (Blueprint $table) {
        $table->increments('id'); 
        $table->string('name');
        $table->integer('number_of_rooms');
}

在之前的项目中，我曾经用来定义与模型的单一关系。我想在桌子上保存预订ID，班级和房间/餐馆ID，班级和班级名称。

在我将单个类的实现定义为

之前

    $boking = Booking::findOrFail($id);
     //Defined relationsip on the model as booking()
    $room->booking()->create($data)

模型如下

Business.php

class Booking extends Model
{

    public function bookings()
    {
        return $this->morphTo();
    }

    public function business()
    {
        return $this->morphTo();
    }
}

在Room.php和Restaurant.php上

public function booking()
    {
        return $this->morphMany(Booking::class, 'booking');
    }

    public function business()
    {
        return $this->morphMany(Booking::class, 'business');
    }