Question

我在fastreport中有以下这些查询。我想通过输入一个查询来总结这两个查询的答案..任何人都可以帮忙吗？

SELECT 
    EAMEMID, COUNT (EAMATTNSTATUS)/2 as ABSENTDAYS1
FROM 
    viewDAILYSUM  
WHERE 
    (EAMEMID = :EAMEMID) 
    AND (EAMDATE BETWEEN :FDate AND :TDate)
    AND (EAMATTNSTATUS IN (7, 8))           
GROUP BY 
    EAMEMID  
ORDER BY 
    EAMEMID

SELECT 
    EAMEMID, COUNT(DISTINCT EAMDATE) ABSENTDAYS        
FROM 
    viewDAILYSUM  
WHERE 
    (EAMEMID = :EAMEMID) 
    AND (EAMDATE BETWEEN :FDate AND :TDate)
    AND (EAMATTNSTATUS IN (6))
GROUP BY 
    EAMEMID
ORDER BY 
    EAMEMID

Answer 1

试试这个：

SELECT EAMEMID, SUM(ABSENTDAYS) AS ABSENTDAYS FROM (
    SELECT  EAMEMID, COUNT (EAMATTNSTATUS)/2 as ABSENTDAYS
    FROM viewDAILYSUM  
    WHERE (EAMEMID = :EAMEMID) 
       AND (EAMDATE BETWEEN :FDate AND :TDate)
       AND (EAMATTNSTATUS IN (7, 8))           
    GROUP BY EAMEMID  
    UNION ALL
    SELECT  EAMEMID, COUNT(DISTINCT EAMDATE) ABSENTDAYS        
    FROM viewDAILYSUM  
    WHERE (EAMEMID = :EAMEMID) 
    AND (EAMDATE BETWEEN :FDate AND :TDate)
    AND (EAMATTNSTATUS IN (6))
    GROUP BY EAMEMID
    )
GROUP BY EAMEMID
ORDER BY EAMEMID

SUM函数用于2个查询

1 个答案: