字符串从给定的最后一个特定关键字

Question

下面是一个完整的字符串，如何将字符串从“{”拆分为“}”意味着需要完整的对象。

  % Total    % Received % Xferd  Average Speed   Time    Time     Time  Current
                                 Dload  Upload   Total   Spent    Left  Speed
100   234    0   159  100    75    584    275 --:--:-- --:--:-- --:--:--   584
{"scope":"Production","token_type":"bearer","expires_in":78,"refresh_token":"eregfgfg","access_token":"swewe23231c323"}

需要结果：

{"scope":"Production","token_type":"bearer","expires_in":78,"refresh_token":"eregfgfg","access_token":"swewe23231c323"}

Answer 1

试试这个

JSON.parse(yourobject) 

Answer 2

这很简单......

var yourObj = yourStr.substring(yourStr.indexof('{'), yourstring.length-1);

或

var yourObj = yourStr.substring(yourStr.indexof('{'), yourStr.indexof('}'));

朋友这只有在您的字符串与您上面写的完全相同时才有效。

Answer 3

使用正则表达式

var a  = '  % Total    % Received % Xferd  Average Speed   Time    Time     Time  Curren Dload  Upload   Total   Spent    Left  Speed 100   234    0   159  100    75    584    275 --:--:-- --:--:-- --:--:--   584 {"scope":"Production","token_type":"bearer","expires_in":78,"refresh_token":"eregfgfg","access_token":"swewe23231c323"}';

console.log((/(\{.*\})/gmi).exec(a)[0]);

显示：“{”范围“：”生产“，”token_type“：”bearer“，”expires_in“：78，”refresh_token“：”eregfgfg“，”access_token“：”swewe23231c323“}”