在ajax

Question

在PHP中，我从foreach获取一个数组。我是JSON编码并立即显示所有结果。这很好用。但是，如果我需要逐个显示数组项目，因为foreach仍在继续？

<?php 
$array = //somearray;
$data_arr = array();
foreach($array as $arr){
//do something
$data_arr[] = $arr;
}
echo json_encode(array('success'=>true,'data'=>$data_arr));
//here i can display the data in my jquery using each function
//i can display the whole data at once after the foreach is completed
//what i need is i want to display first element of data_arr after its loop is completed and then the second element and so on

＆GT;

Answer 1

你试过http://www.php.net/array_shift吗？它的php函数你需要在foreach之后调用这个函数

<?php 
foreach($array as $arr){
//do something
$data_arr[] = $arr;
}

print_r array_shift($data_arr);
//Print First array value from this $data_arr list.

?>

感谢。

Answer 2

您要找的是foreach($array as $key => $val){ if($key == 'product_image'){ echo "<img src='".$val."' />"; } } 。

结帐以下链接，了解如何操作。

https://www.sitepoint.com/php-streaming-output-buffering-explained/