所以我有一个程序可以计算平均成绩,最高成绩,最低成绩,以及没有最低成绩的平均成绩。因此,对于我的方法,确定没有最低等级的新平均值,我想使用我在该方法中找到的最低等级。
/**
* lowestGrade() - method will return lowest grade
* @return lowGrade
*/
public static double lowestGrade(double[] grades) {
double lowGrade = 100.0;
// for loop that goes through grades array and stores
// first grade found as highest grade
for (int i = 0; i < grades.length; i++) {
// if statement will determine true lowest grade
if ( grades[i] < lowGrade ) {
lowGrade = grades[i];
}
}
// Output
return lowGrade;
}
/**
* averageWOLowGrade() - method will calculate average without lowest grade
* @return newAverage
*/
public static void averageWOLowGrade(double[] grades) {
double newAverage = 0;
}
答案 0 :(得分:0)
如上所述[{3}},您可以在字段中存储最低成绩:
{ "TourId":"3", "UserId":"1" }
请记住执行顺序在这里很重要。我宁愿计算两次值,而不是在静态变量中管理状态。甚至更好:在一次运行中计算所有结果:
private static double min = 0.0;
public static double lowestGrade(double[] grades) {
// Set min and return its value.
return min = DoubleStream.of(grades).min().getAsDouble();
}
public static double averageWOLowGrade(double[] grades) {
return DoubleStream.of(grades).filter(x -> x != min)
.average()
.getAsDouble();
}