从数组中替换字符串中的特殊字符

Question

以下是我的代码：

NSString *str = [EpiC objectAtIndex:indexPath.row];
NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\/"];
str = [[str componentsSeparatedByCharactersInSet: doNotWant] componentsJoinedByString: @"\"];
NSLog(@"%@", str); 

显示错误如下： 这一行的未知逃逸序列：

NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\/"];

和意想不到的＆＃39; @＆＃39;在计划中，在这一行：

NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\"];

Answer 1

未知转义序列表示必须使用第二个反斜杠转义反斜杠。

NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\\/"];

额外的反斜杠也解决了意外'@'程序错误。

Answer 2

喜欢

 NSString *str = @"FSJ\/6356232";
NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\\/"];
str = [[str componentsSeparatedByCharactersInSet: doNotWant] componentsJoinedByString: @"\\"];
       NSLog(@"%@", str);

你得到了

的输出

Answer 3

请按照以下步骤确定为您工作。

 NSString *str = @"FSJ\/6356232";
 NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\\/"];
 str = [[str componentsSeparatedByCharactersInSet: doNotWant] componentsJoinedByString: @"\\"];
       NSLog(@"%@", str);