Question

我有一个抽象类，它应该是一个接口：

//hpp
#ifndef IMOVABLE_HPP_INCLUDED
#define IMOVABLE_HPP_INCLUDED

#include "StaticMovementPath.hpp"

class IMovable{
protected:
    StaticMovementPath *staticMovementPath;
public:
    IMovable();
    virtual setStaticMovementPath(StaticMovementPath *staticmovementPath) = 0;
};

#endif // IMOVABLE_HPP_INCLUDED

//cpp
#include "IMovable.hpp"

#include "StaticMovementPath.hpp"

IMovable::IMovable()
{
    staticMovementPath = new StaticMovementPath();
}



//hpp
#ifndef STATICMOVEMENTPATH_HPP_INCLUDED
#define STATICMOVEMENTPATH_HPP_INCLUDED

class StaticMovementPath{
public:
    StaticMovementPath();
};

#endif // STATICMOVEMENTPATH_HPP_INCLUDED

//cpp
#include "StaticMovementPath.hpp"

StaticMovementPath::StaticMovementPath(){
};




//hpp
#ifndef CAMERA_HPP
#define CAMERA_HPP

#include "IMovable.hpp"

class Camera: public IMovable{
public:
    Camera();
};

#endif // CAMERA_HPP

//cpp
#include "Camera.hpp"

#include "IMovable.cpp"

Camera::Camera() : IMovable(){
}

编译它将抛出：

||=== Build: Debug in mapEditor (compiler: GNU GCC Compiler) ===|
obj\Debug\src\Camera.o||In function `ZN8IMovableC2Ev':|
...\src\IMovable.cpp|8|undefined reference to `StaticMovementPath::StaticMovementPath()'|
||error: ld returned 1 exit status|
||=== Build failed: 2 error(s), 0 warning(s) (0 minute(s), 0 second(s)) ===|

如果我没有定义构造函数（因此调用默认构造函数），我没有错误。但是，对于具有一个或多个参数的构造函数，我得到了相同的错误。

我如何使这项工作？

我知道大部分代码似乎毫无意义，但我尽可能地删除它。使用（更多）完整代码抛出相同的错误。

Answer 1

StaticMovementPath.cpp没有针对调试或发布的目标，所以它根本就没有编译。

尝试实现抽象类时未定义的引用错误

1 个答案: