按值对Swift数组字典进行排序

Question

按值排序[String : String]数组的最佳和最有效的方法是什么？

例如，

let dicts = [["key": "4"], ["key": "4"], ["key": "3"], ["key":"1"]]

然后在排序后我想要

dicts = [["key": "1"], ["key": "3"], ["key": "4"], ["key":"4"]]

Answer 1

这有点罗嗦，但它可以让你很好地控制丢失键和非int值。

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如果您对比较更加灵活，并想要更清洁的东西。

var array = [["key": "1"], ["key": "3"], ["key": "2"], ["key":"4"]]
array.sort { (lhs, rhs) -> Bool in
    if let leftValue = lhs["key"], let leftInt = Int(leftValue), let rightValue = rhs["key"], let rightInt = Int(rightValue) {
        return leftInt < rightInt
    } else {
        return false // NOTE: you will need to decide how to handle missing keys and non-int values.
    }
}