Question

如何转换缩写的月份，例如在python中Apr为全名？

Answer 1

如果您坚持按照标签使用datetime，则可以将月份的短版本转换为日期时间对象，然后使用全名重新格式化：

import datetime
datetime.datetime.strptime('apr','%b').strftime('%B')

Answer 2

以下是使用日历库的方法。

>>> import calendar
>>> calendar.month_name [list(calendar.month_abbr).index('Apr')]
'April'
>>>

Answer 3

一个简单的字典就可以了

例如

month_dict = {"jan" : "January", "feb" : "February" .... }

month_dict [ “一月”]

'一月'

Answer 4

一种快速而又肮脏的方式：

conversions = {"Apr": "April", "May": "May", "Dec": "December"}
date = "Apr"

if date in conversions:
    converted_date = conversions[date]

Answer 5

SELECT DISTINCT ?s1 ?s2 {
  ?s1 ?p ?o .   
  ?s2 ?p ?o .
  FILTER NOT EXISTS {
    ?s1 ?p ?o . 
    ?s2 ?p ?o . 
    ?s1 ?p1 ?o1 . 
    FILTER NOT EXISTS { ?s2 ?p1 ?o1 } }
  FILTER NOT EXISTS {
    ?s1 ?p ?o . 
    ?s2 ?p ?o .
    ?s2 ?p2 ?o2 . 
    FILTER NOT EXISTS { ?s1 ?p2 ?o2 } }
  FILTER (STR(?s1) < STR(?s2))
}

确保根据需要转换为适当的情况。

类似地，calendar库也具有import calendar months_dict = dict(zip(calendar.month_abbr[1:], calendar.month_name[1:])) # {'Jan': 'January', 'Feb': 'February', 'Mar': 'March', 'Apr': 'April', 'May': 'May', 'Jun': 'June', 'Jul': 'July', 'Aug': 'August', 'Sep': 'September', 'Oct': 'October', 'Nov': 'November', 'Dec': 'December'}和calendar.day_abbr

Answer 6

这适用于混合缩写和完整月份名称，例如：

Dec 31, 2017
December 31, 2017
Aug 31, 2017
Feb 10, 2018
March 1, 2018
Jun 2, 2019

如果您在Pandas Dataframe中使用实际日期进行操作，那么您就不会这样做希望June最终映射到Junee：

def replace_month_abrev(date_string):
    month_dict = {"Jan ": "January ",
              "Feb ": "February ",
              "Mar ": "March ",
              "Apr ": "April ",
              "May ": "May ",
              "Jun ": "June ",
              "Jul ": "July ",
              "Aug ": "August ",
              "Sep ": "September ",
              "Sept ": "September ",
              "Oct ": "October ",
              "Nov ": "November ",
              "Dec ": "December "}
    # find all dates with abrev
    abrev_found = filter(lambda abrev_month: abrev_month in date_string, month_dict.keys())
    # replace each date with its abbreviation
    for abrev in abrev_found:
        date_string = date_string.replace(abrev, month_dict[abrev])
    # return the modified string (or original if no states were found)
    return date_string

combined['deadline'].map(replace_month_abrev)

将python缩写的月份名称转换为全名

6 个答案: