Oracle SQL查询：如何组合这些结果？

Question

我想将这些涉嫌重复（实际上不是）的条目合并到属性ID（PTY_ID）组下的唯一条目中，这就是结果：

以下是我的查询代码：

➜  new_ghost npm install --production
npm WARN cannot run in wd ghost@0.11.2 node core/server/utils/npm/preinstall.js (wd=/var/www/new_ghost)
[1]    14831 killed     npm install --production

更确切地说，我想显示一个显示许多功能的唯一属性条目。我怎么能这样做？

顺便说一句，我正在使用oracle 11g。所以我尝试了LISTAGG，但效果不好......

[UPDATE]

我只是试图像这样使用LISTAGG：

SELECT distinct P.PTY_ID, (P.PTY_UNITNUM||' '||P.PTY_STREET||', '
       ||P.PTY_SUBURB||', '||P.PTY_CITY||' '||P.PTY_POSTCODE) address,
       T.P_type_name, F.FEAT_name
FROM  property P, PROPERTY_TYPE T, feature F, property_FEATURE K
WHERE  P.P_TYPE_ID = T.P_TYPE_ID
AND   K.feat_id = F.feat_id
AND   K.pty_id = P.pty_id
ORDER BY  p.pty_id;

我收到此错误说：＆＃34; FROM关键字找不到预期位置＆＃34;。错误发生在＆＃34; select distinct P.PTY_ID, (P.PTY_UNITNUM||' '||P.PTY_STREET||', ' ||P.PTY_SUBURB||', '||P.PTY_CITY||' '||P.PTY_POSTCODE) address, T.P_type_name, LISTAGG(F.FEAT_name, ',') WITHIN GROUP (ORDER BY P.PTY_ID) AS FEATURES from property P, PROPERTY_TYPE T, feature F, property_FEATURE K where P.P_TYPE_ID = T.P_TYPE_ID and K.feat_id = F.feat_id and K.pty_id = P.pty_id group by P.PTY_ID, P.PTY_UNITNUM, P.PTY_STREET, P.PTY_SUBURB, P.PTY_CITY, P.PTY_POSTCODE, T.P_type_name order by p.pty_id; ＆＃34;

行中

Answer 1

尝试在'功能'之前删除'AS'...

LISTAGG(F.FEAT_name, ',') WITHIN GROUP (ORDER BY P.PTY_ID) AS FEATURES

LISTAGG(F.FEAT_name, ',') WITHIN GROUP (ORDER BY P.PTY_ID) FEATURES

SELECT DISTINCT P.PTY_ID,
  (P.PTY_UNITNUM
  ||' '
  ||P.PTY_STREET
  ||', '
  ||P.PTY_SUBURB
  ||', '
  ||P.PTY_CITY
  ||' '
  ||P.PTY_POSTCODE) address,
  T.P_type_name,
  LISTAGG(F.FEAT_name, ',') WITHIN GROUP (ORDER BY P.PTY_ID) FEATURES
FROM property P,
  PROPERTY_TYPE T,
  feature F,
  property_FEATURE K
WHERE P.P_TYPE_ID = T.P_TYPE_ID
AND K.feat_id     = F.feat_id
AND K.pty_id      = P.pty_id
GROUP BY P.PTY_ID,
  P.PTY_UNITNUM,
  P.PTY_STREET,
  P.PTY_SUBURB,
  P.PTY_CITY,
  P.PTY_POSTCODE,
  T.P_type_name
ORDER BY p.pty_id;