Question

我遇到了SELECT查询的问题。查询仅输出一个结果，而不是此数据库中的所有行。

有谁知道为什么？

$select_comments_sql = "
    SELECT * 
    FROM home_comments
    ORDER BY id DESC
";
  if ($select_comments_stmt = $con->prepare($select_comments_sql)) {
        //$select_comments_stmt->bind_param("s", $user_id);
        $select_comments_stmt->execute();
        if (!$select_comments_stmt->errno) {
            //echo "error";
        }
        $select_comments_stmt->bind_result($comment_id, $comment_user_id, $comment_username, $home_comments, $comment_date);

        $comment_array = array();
        while ($select_comments_stmt->fetch()) {
            $comment_array[] = $comment_user_id;
            $comment_array[] = $comment_username;
            $comment_array[] = $home_comments;
            $comment_array[] = $comment_date;
        }
        if ($home_comments === NULL) {
            echo 'No comments found.';
        } else {
            echo $comment_username. "<br>";
            echo $home_comments. "<br><br><br>";
        }
  }

AJAX

$("#comment-form").on("submit", function (event) {
    event.preventDefault();

    var home_comment = $("#home_comment").val();

    $.ajax({ 
        url: "ajax-php/comment-send.php", 
        type: "POST",
        data: {
            "home_comment": home_comment
        },
        success: function (data) {
        //  console.log(data); // data object will return the response when status code is 200
            if (data == "Error!") {
                alert("Unable to post comment!");
                alert(data);
            } else {
                $("#comment-form")[0].reset();
                //$('.newsletter-popup').fadeIn(350).delay(2000).fadeOut();
            }
        },
        error: function (xhr, textStatus, errorThrown) {
            alert(textStatus + " | " + errorThrown);
            console.log("error"); //otherwise error if status code is other than 200.
        }
    });
});

PHP

$user = new User();

    $home_comment = $_POST['home_comment'];
    $username = $user->data()->username;
    $okay = true;

    if ( $okay ) { 

        $comment_insert = "
            INSERT INTO home_comments 
            (id, user_id, username, comment, date)
            VALUES(?, ?, ?, ?, NOW())
            ";
        $comment_stmt = $con->prepare($comment_insert);
        $comment_stmt->bind_param('ssss', $id, $user_id, $username, $home_comment);
        $comment_stmt->execute();
        }

Answer 1

您正在输出while循环之外的结果。由于您将整个结果集存储到$comment_array[]中，因此您也可以将其转储，以获取从DB获取的所有注释，或者将它们输出到循环内。

if ($select_comments_stmt = $con->prepare($select_comments_sql)) {
    //$select_comments_stmt->bind_param("s", $user_id);
    $select_comments_stmt->execute();
    if (!$select_comments_stmt->errno) {
        //echo "error";
    }
    $select_comments_stmt->bind_result($comment_id, $comment_user_id, $comment_username, $home_comments, $comment_date);

    $comment_array = array();
    while ($select_comments_stmt->fetch()) {
        $comment_array[] = $comment_user_id;
        $comment_array[] = $comment_username;
        $comment_array[] = $home_comments;
        $comment_array[] = $comment_date;
        if ($home_comments === NULL) {
            echo 'No comments found.';
        } else {
            echo $comment_username. "<br>";
            echo $home_comments. "<br><br><br>";
        }
    }
    // Alternatively: print_r($comment_array);
}

Answer 2

您编写的代码存在几个问题。首先，您要在$comment_array数组中附加每列的值。您应该在while循环中创建一个子数组，并在$comment_array中创建一个子数组以生成多维数组。

其次，您只显示$comment_username的值，该值将是while循环中的最后一个用户名。

您应该遍历$comment_array并单独显示每个用户名和评论。

代码看起来像这样，

    $comment_array = array();
    while ($select_comments_stmt->fetch()) {
        $sub_array=array();
        $sub_array["userid"] = $comment_user_id;
        $sub_array["username"] = $comment_username;
        $sub_array["comments"] = $home_comments;
        $sub_array["date"] = $comment_date;
        $comment_array[]=$sub_array;
    }
    if ($home_comments === NULL) {
        echo 'No comments found.';
    } else {
        echo $comment_username. "<br>";
        echo $home_comments. "<br><br><br>";

        // Loop over comments array.

        foreach($comment_array as $comment) {
            echo $comment["username"]. "<br>";
            echo $comment["comments"]. "<br><br><br>";
        }
    }

SELECT查询仅输出一个结果

2 个答案: