Question

我正在进行设施预订申请，该申请允许用户搜索设施，具有给定的设施类型，日期，入住和退房时间。

例如：用户在20-08-2016搜索羽毛球场，并且入住时间是18:00到20:00（退房时间），数据库存在记录是从18:00到20:00，它应该返回＆＃34;不可用＆＃34;，到目前为止运行良好。但如果入住时间是18:30，结账时间是19:30，即18:00到20:00之间，则不会显示＆＃34;不可用＆＃34;。

所以我的问题是，如何使18:00到20:00成为一个插槽，并阻止登记和退房时间之间的时间，以防止它显示不同的结果。

我尝试在PHP中包含此代码，但它不起作用

if($response["time_in"]<$time_in<$response["time_out"]) echo "Not Available"; else if($response["time_in"]<$time_out<$response["time_out"]) echo "Not Available";

这是我的整个search.php文件，用于从数据库中检索数据

Ps：time_in相当于入住时间， time_out相当于退房时间

?php
$con = mysqli_connect("mysql1.000webhost.com" , "a6539091_UD" , "0108981390" , "a6539091_UD") or die(mysql_error());

$venue = $_POST["Venue"];
$facility = $_POST["Facility"];
$date = $_POST["Date"];
    $time_in = $_POST["Time_in"];
    $time_out = $_POST["Time_out"];

$selectquery = mysqli_prepare($con, "SELECT * FROM SearchAva WHERE (Venue = ? AND Facility = ? AND Date = ? AND Time_in = ? AND Time_out = ?)");
mysqli_stmt_bind_param($selectquery, "sssss", $venue, $facility, $date, $time_in, $time_out);
mysqli_stmt_execute($selectquery);

mysqli_stmt_store_result($selectquery);
mysqli_stmt_bind_result($selectquery, $venue, $facility, $date, $time_in, $time_out);

$response = array();

while(mysqli_stmt_fetch($selectquery)){  
    $response["venue"] = $venue;
    $response["facility"] = $facility;
    $response["date"] = $date;
    $response["time_in"] = $time_in;
    $response["time_out"] = $time_out;
}

if($time_in>$response["time_in"] && $time_in<$response["time_out"])
 echo "Not Available";

    else if($time_out>$response["time_in"]&& $time_out<$response["time_out"])
 echo "Not Available";

echo json_encode($response);

mysqli_stmt_close($selectquery);
mysqli_close($con);
?>

在MySQL数据库中为预订系统定义一个时间段

0 个答案: