Question

I have this query here:

SELECT a.timeSlot, a.dateSlot, COUNT(concat(b.dateSlot, ' - ', b.timeSlot)) AS counter 
FROM CP_VIP_Preview_TimeSlots as a 
   LEFT OUTER JOIN [CP-VIP-Preview] as b 
                ON a.timeSlot = b.dateSlot 
               AND a.dateSlot = b.timeSlot 
GROUP BY a.timeSlot, a.dateSlot, a.[order] 
ORDER BY a.[order]

What I am trying to do is get a count of each, which this query does, but something is messed up, any rows that have 0 appear as 1 and any row that actually has an items show the correct number, my problem if the row count is 0 its displaying 1....why is it doing that?

Answer 1

您的COUNT(concat(b.dateSlot, ' - ', b.timeSlot))将始终返回至少一个

也许你可以试试

sum(IIF(b.dateSlot is null,0,1))

Answer 2

你需要在使用group by之后使用HAVING来应用过滤器，这样你就不会将记录计为零

SELECT a.timeSlot, a.dateSlot, COUNT(concat(b.dateSlot, ' - ', b.timeSlot)) AS counter 
FROM CP_VIP_Preview_TimeSlots as a 
   LEFT OUTER JOIN [CP-VIP-Preview] as b 
                ON a.timeSlot = b.dateSlot 
               AND a.dateSlot = b.timeSlot 
GROUP BY a.timeSlot, a.dateSlot, a.[order] 
ORDER BY a.[order]

HAVING COUNT（concat（b.dateSlot，' - '，b.timeSlot））＆gt; 0

SQL LEFT OUTER JOIN with Count

2 个答案: