Question

你好我需要计算这个时间戳事务列的时差，格式如下，我正在试图使用DATEDIFF函数无济于事。谢谢你的帮助。

Txtimestamp
2016-01-05 12:16:51.000
2016-01-05 12:16:51.000
2016-01-18 12:24:16.000
2016-01-18 12:24:16.000
2016-01-20 08:15:32.000
2016-01-20 08:15:32.000
2016-01-20 12:24:29.000
2016-01-20 12:24:29.000
2016-01-29 12:18:11.000
2016-01-29 12:18:11.000
2016-02-01 12:16:43.000
2016-02-01 12:16:43.000

Answer 1

你想要这样的东西吗？

select datediff(second, lag(txtimestamp) over (order by txtimestamp), txtimestamp) as diff_in_seconds
from t;

Answer 2

我心中有这样的东西，但它并不像戈登的答案那样清脆。我不确定性能差异是什么。可能很多，因为这需要执行两个子查询...

 SELECT tA.txtimestamp, tB.txtimestamp, DATEDIFF(second, tA.txtimestamp, tB.txtimestamp) AS diff
 FROM (SELECT row_num = ROW_NUMBER() OVER (ORDER BY txtimestamp), txtimestamp
       FROM your_table) AS tA 
       INNER JOIN
      (SELECT row_num = ROW_NUMBER() OVER (ORDER BY txtimestamp), txtimestamp
       FROM your_table) AS tB ON tA.row_num = tB.row_num - 1

它很笨重，但肯定是另一种可能性。您需要将连接条件中的“ - ”修改为“+”，具体取决于您希望如何产生差异。

SQL Server 2012查询计算日期和时间差异

2 个答案: