Question

我想知道是否有办法让这项工作成功。我正在推导一个表“WHERE lie_start ='green'”（以及一些我不想重复的其他条件），需要从中获取数字（以及其他一些信息）。另外，我需要附加条件为lie_finish ='holed'的条目数。目前我得到错误：表mydb.x不存在。

    private IntentFilter intentFilter;

static {
    intentFilter = new IntentFilter();
    intentFilter.addAction(Intent.ACTION_TIME_TICK);
    intentFilter.addAction(Intent.ACTION_UNINSTALL_PACKAGE);
}

private final BroadcastReceiver receiver = new BroadcastReceiver() {
    @Override
    public void onReceive(Context context, Intent intent) {
        final String action = intent.getAction();
        if (action.equals(Intent.ACTION_UNINSTALL_PACKAGE) {
            Log.e("App", "Uninstalling");
        } else if (action.equals(Intent.ACTION_TIME_TICK){
        // this works
        }
    }
};

Answer 1

您需要重复表名。表别名无法识别：

SELECT COUNT(*) AS total, 
       (SELECT COUNT(*) FROM mydb.strokes WHERE lie_finish='holed') as holed
FROM (SELECT * FROM mydb.strokes WHERE lie_start='green') as x;

然而，这更简单地写为：

select count(*) as total, sum(lie_finish = 'holed') as holed
from mydb.strokes s
where lie_start = 'green';

select语句中的子查询无法找到派生表？

1 个答案: