Question

任务是，设计并实现一个应用程序，打印旅行歌曲“一百瓶啤酒”的前几节经文。使用循环，每次迭代打印一节经文。从使用中读取要打印的经文数量并验证输入。＆＃34;我在遇到for循环时遇到了一些麻烦。这是我到目前为止所做的，但我很确定我已经离开了。有什么指针吗？

    int verse;
    int count;
    System.out.println("number of verses?");
    verse = scan.nextInt();
    for(count= verse; count >= (verse - 3); count--)
    {
        System.out.println(verse + " bottles of beer on the wall");
        System.out.println(verse + " bottles of beer");
        System.out.println("If one of those bottles should happen to fall");
        System.out.println(count + " bottles of beer on the wall");
        System.out.println(count + " bottles of beer on the wall");
        System.out.println(count + " bottles of beer");
        System.out.println("If one of those bottles should happen to fall");
        System.out.println(count + " bottles of beer on the wall");

    }

Answer 1

您应该在for表达式中声明您的计数，而不是在for循环之外。你也只需要3行歌曲，因为它们会重复，直到完成循环。

for (int count = verse; count >= 3; count--) {
    System.out.println(count + " bottles of beer on the wall");
    System.out.println(count + " bottles of beer");
    System.out.println("If one of those bottles should happen to fall");
    System.out.println((count - 1) + " bottles of beer on the wall");
}

你最大的问题是你的循环中有verse，但它并没有改变。 count跟踪循环的当前索引，而verse只跟踪要执行的循环数。

注意最后一行有(count - 1)暂时显示它将减少的下一个数字。

此外，我删除了(verse - 3)并将其替换为3因为我认为您想要循环直到只剩下3瓶。否则请将此号码更改为1。

Answer 2

您还可以使用while循环。

var START = 99;

var i = START + 1;
while(i--) {
    System.out.println(i + " bottles of beer on the wall");
    System.out.println(i + " bottles of beer");
    System.out.println("If one of those bottles should happen to fall");
    System.out.println(i + " bottles of beer on the wall");
}

墙上的99瓶啤酒代码

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