Question

两个表，每个表都有employee_id和manager_id，链接到employee_id表有不同的employee_id。

UPDATE employee u
SET u.manager_id = (SELECT m.id
    FROM employee e
    JOIN old_db.employees oe ON e.last_name = oe.last_name
    JOIN old_db.employees om ON oe.manager_id = om.employee_id
    INNER JOIN employee m ON m.last_name = om.last_name
    WHERE e.id = u.id)
WHERE manager_id IS NULL;

给出

ERROR at line 2: ORA-01427: single-row subquery returns more than one row

我已尝试rownum=1，但这会使所有manager_id相同。

选择一个给定employee_id的查询会返回一个值

SQL> SELECT m.id
  2     FROM employee e
  3     JOIN old_db.employees oe ON e.last_name = oe.last_name
  4     JOIN old_db.employees om ON oe.manager_id = om.employee_id
  5     INNER JOIN employee m ON m.last_name = om.last_name
  6     WHERE e.id = 1805;

        ID
----------
      1804

Answer 1

问题的根本原因在表employees或表employee last_name中并不是唯一的。当你在姓氏上加入表格时，你会得到更多的一行。您可以使用下一个查询进行检查：

SELECT e.id, count(*), count(distinct m.id)
FROM employee e
JOIN old_db.employees oe ON e.last_name = oe.last_name
JOIN old_db.employees om ON oe.manager_id = om.employee_id
INNER JOIN employee m ON m.last_name = om.last_name
GROUP BY e.id;

可能存在更合适的列加入它，例如employee_id，如果这样，您的查询可能会被重写为：

UPDATE employee u
SET u.manager_id = (SELECT oe.manager_id 
                    FROM old_db.employees oe
                   WHERE oe.employee_id = u.id)
WHERE manager_id IS NULL;

ORA-01427 UPDATE自加入ORACLE

1 个答案: