Question

我有要读取的CSV文件，我存储在字符串中，我需要在每个＆＃34;，＆＃34;我的意见就像

名称，ID，说明，emailId Micheal，234655，＆＃34;下一行问题的测试说明谢谢和问候，Mike＆＃34;，Mike @ yahoo.com

请帮助我。

此致维杰

enter code here

import java.io.*;
import java.util.logging.*;
import java.util.ArrayList;
import java.util.List;
public class ReadingCSVFile {

 public static void main(String args[])
 {
    StringBuilder sb =new StringBuilder();
    int n;
    String inputStream;
    String Name[] =new String[30];
    List l1 = new ArrayList();
    try
    {
         FileInputStream fis =new  fileInputStream("C:/Users/vijaykumar.naga/Desktop/Abc.txt"); 
     FileOutputStream fos = new FileOutputStream("C:/Users/vijaykumar.naga/Desktop/Output.txt");
     int ch;
     while((ch = fis.read()) != -1){
         sb.append((char)ch);
     }
     System.out.println("The InputString is " +sb.toString());
     String abcd =sb.toString();
       for(int i=0; i<30; i++)
         {
         l1.add(abcd.split(","));
         System.out.println("The Names are " +l1);
          }

        }
    catch(Exception e)
     {

      }
    }

  }

Answer 1

请参阅代码的修订版并附上说明：

import java.io.*;
import java.util.logging.*;
import java.util.ArrayList;
import java.util.List;
public class ReadingCSVFile {

 public static void main(String args[])
 {
    StringBuilder sb =new StringBuilder();
    int n;
    String inputStream;
    String Name[] =new String[30];
    List<String> l1 = new ArrayList<>(); //Use generics <> operator
    try
    {
         FileInputStream fis =new  fileInputStream("C:/Users/vijaykumar.naga/Desktop/Abc.txt"); 
     FileOutputStream fos = new FileOutputStream("C:/Users/vijaykumar.naga/Desktop/Output.txt");
     int ch;
     while((ch = fis.read()) != -1){
         sb.append((char)ch);
     }
     System.out.println("The InputString is " +sb.toString());
     String abcd =sb.toString();
       /*for(int i=0; i<30; i++)
         {
         l1.add(abcd.split(","));           //This is wrong. abcd.split(",") will return String[]
         System.out.println("The Names are " +l1);
          }

        }*****This loop is not needed*/ 
    //As you already read the content in abcd variable, do as follows
    l1.addAll(Arrays.asList(abcd.split(",")));

    catch(Exception e)
     {

      }
    }

  }

Answer 2

这是我用来读取CSV文件的简单解决方案。

    Scanner sc = null;
    try {
        sc = new Scanner(new File("test.csv"));
        String s = null;
        String[] array;
        while(sc.hasNext()){
            s = sc.nextLine();
            array = s.split(",");
            System.out.println(Arrays.toString(array));
        }
    } catch (FileNotFoundException ex) {
        ex.printStackTrace();
    } finally {
        if(sc != null) sc.close();
    }

基本上，这将使用扫描仪一次读取一行，可能不是最好的但是40行，我真的不在乎;）

然后，我使用逗号分割行，小心如果在值中使用,，则不在此处进行检查。

然后，我在控制台中打印数组。

编辑：

try (Scanner sc = new Scanner(new File("test.csv"))){
        String s = null;
        String[] array;
        while(sc.hasNext()){
            s = sc.nextLine();
            array = s.split(",");
            // Do what you want with the array, here I just print the result
            System.out.println(Arrays.toString(array));
        }
    } catch (FileNotFoundException ex) {
        ex.printStackTrace();
    }

Answer 3

我建议使用正则表达式：
（[A-ZA-Z] +）\，（\ d +）\，（\ “+ \”。。| +）\，（\ W + @ \ W + \ W +）

Answer 4

您可以尝试split（）

使用以下语法

String[] parts = string.split(",");

或者您可以将StringTokenizer与令牌,

一起使用

希望这有帮助

拆分字符串并存储在数组中

4 个答案: