列名称无效' FinalTotal'

时间:2016-10-26 00:09:44

标签: sql sql-server

SELECT 
    o.OrderID, ProductName, OrderDate, ItemPrice, TaxAmount, 
    DiscountAmount, DiscountAmount - ItemPrice AS FinalTotal, 
    Quantity, ShipDate,FinalTotal * Quantity AS ItemTotal
FROM
    Orders AS o 
JOIN 
    OrderItems AS oi ON o.OrderID = oi.OrderID
JOIN 
    Products AS p ON oi.ProductID = p.ProductID;

这是我的代码,它一直说无效的列名称' FinalTotal'。我在这里做错了什么?

4 个答案:

答案 0 :(得分:5)

你不能在同一个查询级别上使用列别名。

在计算ItemTotal

时使用FinalToal的完整表达式
SELECT o.OrderID, ProductName, OrderDate, ItemPrice, TaxAmount, DiscountAmount,
       DiscountAmount - ItemPrice AS FinalTotal, 
       Quantity, ShipDate,
       (DiscountAmount - ItemPrice) * Quantity AS ItemTotal
FROM Orders AS o JOIN OrderItems AS oi
    ON o.OrderID = oi.OrderID
 JOIN Products AS p
    ON oi.ProductID = p.ProductID;

或者是使用派生查询或CTE

答案 1 :(得分:3)

在SQL Server中执行此操作的一个技巧是使用apply

SELECT o.OrderID, ProductName, OrderDate, ItemPrice, TaxAmount, 
       DiscountAmount, x.FinalTotal, Quantity, ShipDate,
       x.FinalTotal * Quantity AS ItemTotal
FROM Orders o JOIN
     OrderItems AS oi
     ON o.OrderID = oi.OrderID JOIN
     Products AS p
     ON oi.ProductID = p.ProductID CROSS APPLY
     (SELECT (DiscountAmount - ItemPrice) as FinalTotal) x

答案 2 :(得分:2)

您无法在同一查询中引用派生值

尝试

SELECT o.OrderID
, ProductName
, OrderDate
, ItemPrice
, TaxAmount
, DiscountAmount
,DiscountAmount - ItemPrice AS FinalTotal
, Quantity
, ShipDate
,(DiscountAmount - ItemPrice) * Quantity AS ItemTotal
FROM Orders AS o JOIN OrderItems AS oi
    ON o.OrderID = oi.OrderID
 JOIN Products AS p
    ON oi.ProductID = p.ProductID;

答案 3 :(得分:0)

简单地说,因为您的表中没有名为FinalTotal的列,所以这是一个计算的

请改用以下内容......

        SELECT o.OrderID, ProductName, OrderDate, ItemPrice, TaxAmount, DiscountAmount,
       DiscountAmount - ItemPrice AS FinalTotal, 
       Quantity, ShipDate,
       (DiscountAmount - ItemPrice) * Quantity AS ItemTotal
FROM Orders AS o JOIN OrderItems AS oi
    ON o.OrderID = oi.OrderID
 JOIN Products AS p ON oi.ProductID = p.ProductID;