Question

编写一个将一些员工数据从一种格式转换为另一种格式的函数。

论证看起来像这样：

[  
  [  
    ['firstName', 'Joe'], ['lastName', 'Blow'], ['age', 42], ['role', 'clerk']
  ], 
  [
    ['firstName', 'Mary'], ['lastName', 'Jenkins'], ['age', 36], ['role', 'manager']
  ]
]

鉴于输入，返回值应如下所示：

 [ {firstName: 'Joe', lastName: 'Blow', age: 42, role: 'clerk'},
   {firstName: 'Mary', lastName: 'Jenkins', age: 36, role:'manager'}]

我知道这不是最有效的代码，但我仍然无法让新数组包含对象的每次迭代。我也不一定想要一个新阵列。如何将记录为“person”的内容放入数组中，例如示例的输出。

function keyValue (){
var arr3 = [];
var person = {}; 

for (var i = 0; i < arr.length; i++){
     for (var j = 0; j < arr[i].length; j++){
         var key = arr[i][j][0];
         var val = arr[i][j][1];
         person[key]  = val;
        }
    arr3[i] = person;
   }
  console.log(person) // desired output, but not returned
  return arr3;        // either only one instance "joe"  or 2
                      // "marys" depending on where I return
}
keyValue(arr)

 //console.logged()
    { firstName: 'Joe', lastName: 'Blow', age: 42, role: 'clerk' }
{ firstName: 'Mary',
  lastName: 'Jenkins',
  age: 36,
  role: 'manager' }

 //returned
=> [ { firstName: 'Mary',
    lastName: 'Jenkins',
    age: 36,
    role: 'manager' },
  { firstName: 'Mary',
    lastName: 'Jenkins',
    age: 36,
    role: 'manager' } ]

Answer 1

您需要为每个阵列创建一个person对象。在第二个var person = {}循环

之前，在for循环内移动for

＆＃13;

var arr = [
  [
    ['firstName', 'Joe'],
    ['lastName', 'Blow'],
    ['age', 42],
    ['role', 'clerk']
  ],
  [
    ['firstName', 'Mary'],
    ['lastName', 'Jenkins'],
    ['age', 36],
    ['role', 'manager']
  ]
]

function keyValue(arr) {
  var arr3 = [];
  for (var i = 0; i < arr.length; i++) {
    var person = {};
    for (var j = 0; j < arr[i].length; j++) {
      var key = arr[i][j][0];
      var val = arr[i][j][1];
      person[key] = val;
    }
    arr3[i] = person;
  }
  return arr3; 
}

var res = keyValue(arr);
console.log(res);

＆＃13;

您也可以使用.map()，for..of循环

＆＃13;

var arr = [
  [
    ['firstName', 'Joe'],
    ['lastName', 'Blow'],
    ['age', 42],
    ['role', 'clerk']
  ],
  [
    ['firstName', 'Mary'],
    ['lastName', 'Jenkins'],
    ['age', 36],
    ['role', 'manager']
  ]
];

var res = arr.map(array => {
  var obj = {};
  for (var [key, value] of array) {
    obj[key] = value
  }
  return obj
});

console.log(res);

＆＃13;

将嵌套的subArrays转换为数组内的对象键/值对

1 个答案: