Question

我想拆分我的查询，但没有得到完全符合我要求的答案。

我的字符串如下：

选择1;选择\\ 2;选择3 \\;从＆＃39; s复制客户：// mybucket / mydata＆＃39;凭证＆＃39; aws_access_key_id = access_key \\; aws_secret_access_key = secret_key \\; master_symmetric_key = master_key＆＃39;

期望的输出：

选择1

选择\\ 2

选择3 \\

从＃mybucket / mydata＆＃39;复制客户凭证＆＃39; aws_access_key_id = access_key \\; aws_secret_access_key = secret_key \\; master_symmetric_key = master_key＆＃39;

我找到了关于escaper的解决方案。但它并不符合我的要求。

（小于？！\\）;

Handling delimiter with escape characters in Java String.split() method

如何在引号中忽略escape +分号？

帮助我。

Answer 1

我认为这是一种解决方案：

String line = "select 1;select \\2; select 3\\;copy customer from 's3://mybucket/mydata' credentials 'aws_access_key_id=access_key\\;aws_secret_access_key=secret_key\\;master_symmetric_key=master_key'";
line = line.replace("\\","\\\\");//To avoid missing \
String[] tokens = line.split(";(?=([^']*'[^']*')*[^']*$)");//To split on semmicolons, but not those inside quotes
for(String t : tokens) {
    System.out.println("> "+t);
}

你可以在这里测试一下 http://rextester.com/MLTA75734

Answer 2

您可以使用外部.jar 比如，commons-lang-2.6.jar

String str = "select 1;select \\2; select 3\\;copy customer from 's3://mybucket/mydata' credentials 'aws_access_key_id=access_key\\;"
            + "aws_secret_access_key=secret_key\\;"
            + "master_symmetric_key=master_key'";
    str = StringEscapeUtils.escapeJavaScript(str); // method from external jar
    String st[] = str.split(";");
    for(int i=0;i<st.length;i++)
    System.out.println(st[i]);

希望它对你有所帮助......

Answer 3

我尝试了另一种溶剂，这次没有正则表达式。我用尽可能多的奇怪的字符串检查了这个，并且它按照我的预期工作（希望它能像你期望的那样工作），请检查一下。

       String s ="select 1;r;select \\2; select 3\\;copy customer from 's3://mybucket/mydata' credentials 'aws_access_key_id=<access-key-id>\\;aws_secret_access_key=<secret-access-key>\\;master_symmetric_ke‌y=<master-key>'";
               //"select 1;r;select \\2; select 3\\;copy customer from 'r;s3://mybucket/mydata;r' credentials 'a_key;b_key;c_key\\;r' 'aws_access_key_id=access_key\\;aws_secret_access_key=secret_key\\;master_symmetric_key=master_key'";
       s = s.replace("\\","\\\\");
       List<String> tokens = new ArrayList<String>();               
       int i = 0;    
       int j = 0;
       String backup = s;
       while (i < s.length()){
        char c  = s.charAt(i);      
          if(c==';'){
            String previous = s.substring(0,i);
            int quotesBefore = StringUtils.countMatches(backup.substring(0,j), "'");
            if(i<2 || quotesBefore==0 || (i>1 && (quotesBefore & 1) == 0 || ((quotesBefore & 1) != 0) && !(s.charAt(i-1)=='\\' && s.charAt(i-2)=='\\'))){//Even quotes before OR (odd quotes AND not \\ right before)                 
                tokens.add(previous);
                if(i>0)s=s.substring(i+1);
                i=0;
            }
          }
          i++;j++;
        }
        tokens.add(s);
        for(String t : tokens) {
            System.out.println("> "+t);
        }

基本步骤：

重写字符串
每个人检查一下它是否是分号
如果这是真的，请在此之前获取字符，计算引号并添加列表中的那些字符只有在奇数或奇数时才会出现数字，但分号不会使用“\\”

Answer 4

我使用了以下解决方案，用于带引号（'和“）和转义（\）字符的通用刺痛分离器。

public static List<String> split(String str, final char splitChar) {
    List<String> queries = new ArrayList<>();
    int length = str.length();
    int start = 0, current = 0;
    char ch, quoteChar;
    
    while (current < length) {
        ch=str.charAt(current);
        // Handle escape char by skipping next char
        if(ch == '\\') {
            current++;
        }else if(ch == '\'' || ch=='"'){ // Handle quoted values
            quoteChar = ch;
            current++;
            while(current < length) {
                ch = str.charAt(current);
                // Handle escape char by skipping next char
                if (ch == '\\') {
                    current++;
                } else if (ch == quoteChar) {
                    break;
                }
                current++;
            }
        }else if(ch == splitChar) { // Split sting
            queries.add(str.substring(start, current + 1));
            start = current + 1;
        }
        current++;
    }
    // Add last value
    if (start < current) {
        queries.add(str.substring(start));
    }
    return queries;
}

public static void main(String[] args) {

    String str = "select 1;select \\\\2; select 3\\\\;copy customer from 's3://mybucket/mydata' credentials 'aws_access_key_id=access_key\\\\;aws_secret_access_key=secret_key\\\\;master_symmetric_key=master_key'";
    List<String> queries = split(str, ';');
    System.out.println("Size: "+queries.size());
    for (String query : queries) {
        System.out.println(query);
    }
}

得到结果

Size: 4
select 1;
select \\2;
 select 3\\;
copy customer from 's3://mybucket/mydata' credentials 'aws_access_key_id=access_key\\;aws_secret_access_key=secret_key\\;master_symmetric_key=master_key'

Java：拆分以分号分隔的字符串，但忽略引号中的escape +分号

4 个答案: