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时间:2016-10-28 13:52:16

标签: sql oracle

我有一个包含用户ID的表和另一个包含层次结构元素的表。具有用户标识的表具有包含层次结构元素的表的唯一键。我想要完成的是显示每个元素 用户的层次表。问题是我有遍历和显示的层次结构节点。以下是我使用的表格以及我使用的数据的示例。

create table fsecure(
userid varchar(100),
f_element varchar(6)
);

REM INSERTING into FSECURE
SET DEFINE OFF;
Insert into FSECURE (USERID,F_ELEMENT) values ('FFA','140');
Insert into FSECURE (USERID,F_ELEMENT) values ('FFA','280');
Insert into FSECURE (USERID,F_ELEMENT) values ('GGA','202118');
Insert into FSECURE (USERID,F_ELEMENT) values ('GGA','140');
Insert into FSECURE (USERID,F_ELEMENT) values ('RFA','202116');



CREATE TABLE "FVAL" 
   ( "FUND" VARCHAR2(6 ), 
     "FUND_PRED" VARCHAR2(6)
   ) 

REM INSERTING into FVAL
SET DEFINE OFF;
Insert into FVAL (FUND,FUND_PRED) values ('140',null);
Insert into FVAL (FUND,FUND_PRED) values ('280',null);
Insert into FVAL (FUND,FUND_PRED) values ('2000','140');
Insert into FVAL (FUND,FUND_PRED) values ('20001','2000');
Insert into FVAL (FUND,FUND_PRED) values ('20002','2000');
Insert into FVAL (FUND,FUND_PRED) values ('20003','2000');
Insert into FVAL (FUND,FUND_PRED) values ('202118','2000');
Insert into FVAL (FUND,FUND_PRED) values ('2800','280');
Insert into FVAL (FUND,FUND_PRED) values ('280001','2800');
Insert into FVAL (FUND,FUND_PRED) values ('280002','2800');
Insert into FVAL (FUND,FUND_PRED) values ('280003','2800');
Insert into FVAL (FUND,FUND_PRED) values ('280004','2800');

这是一个查询,适用于我只为一个用户执行此操作的时间。

  SELECT      F.FUND
     FROM        FVAL F
     CONNECT BY PRIOR F.FUND    =   F.FUND_PRED
     START WITH  F.FUND  IN ( SELECT F_ELEMENT  FROM FSECURE WHERE USERID = 'FFA' );

我想使这个通用足以显示每个来自fsecure的用户的元素。

预期输出(注意:我只显示一个用户,但我想为桌面上的每个用户执行此操作

"FUND"  "'FFA'"
"140"   "FFA"
"2000"  "FFA"
"20001" "FFA"
"20002" "FFA"
"20003" "FFA"
"202118"    "FFA"
"280"   "FFA"
"2800"  "FFA"
"280001"    "FFA"
"280002"    "FFA"
"280003"    "FFA"
"280004"    "FFA"

非常感谢任何帮助。

2 个答案:

答案 0 :(得分:2)

嗯,据我所知你可以使用类似的东西:

SELECT s.USERID,  hier_f.FUND
   FROM FSECURE s 
   JOIN (  SELECT  F.FUND, connect_by_root(F.FUND) as root_fund
     FROM    FVAL F
     CONNECT BY PRIOR F.FUND    =   F.FUND_PRED
     START WITH  F.FUND  IN ( SELECT F_ELEMENT  FROM FSECURE)) hier_f 
   on s.F_ELEMENT =  hier_f.root_fund

答案 1 :(得分:2)

我认为这就是您所追求的目标:

SELECT     fv.fund,
           connect_by_root(fs.userid) userid
FROM       fval fv
           FULL OUTER JOIN fsecure fs ON (fs.f_element = fv.fund) -- maybe left outer join?
CONNECT BY PRIOR fv.fund = fv.fund_pred
START WITH fs.userid IS NOT NULL
ORDER BY   connect_by_root(fs.userid),
           connect_by_root(fs.f_element),
           LEVEL,
           fv.fund;

FUND   USERID
------ ------
140    FFA
2000   FFA
20001  FFA
20002  FFA
20003  FFA
202118 FFA
280    FFA
2800   FFA
280001 FFA
280002 FFA
280003 FFA
280004 FFA
140    GGA
2000   GGA
20001  GGA
20002  GGA
20003  GGA
202118 GGA
202118 GGA
       RFA

N.B。我不确定您是否希望RFA用户ID显示在输出中,因为它在fval表中没有相应的基金。如果您不想在输出中使用RFA用户标识,则只需将完整的外连接转换为左外连接。

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