Question

我正在尝试计算学生的年龄，我已将他们的值存储在数组中，如下所示：

$day = array(30, 03);
$month = array(07, 12);
$year = array(1998, 1997);

我想计算他们当前的年龄和以下结果。那么，我怎样才能计算出他们在阵列中的年龄。

$age = array(18, 19);

Answer 1

您可以使用array_map并使用封闭内的DateTime::diff返回差异。

$day = array(30, 03);
$month = array(07, 12);
$year = array(1998, 1997);
$now = new DateTime();

$age = array_map(function($year, $month, $date) use ($now) {
    return (new DateTime($year . '-' . $month . '-' . $date))->diff($now)->y;
}, $year, $month, $day);

Answer 2

我假设所有三个数组都有相同的数：

$age=[];

for($i=0;$i<count($day);$i++)
{
$date= $day[$i]."-".$month[$i]."-".$year[$i];
$from = new DateTime($date);
$to   = new DateTime('today');
$diff = $from->diff($to)->y;
array_push($age,$diff);
}
print_r($age);

Answer 3

演示：https://eval.in/668554

解决方案：

$day = array(30, 03, 23);
$month = array(07, 12, 03);
$year = array(1998, 1997, 1987);
$age = [];

$now = new DateTime('today');

for ($i = 0; $i < count($day); $i++) {
    $d = $day[$i];
    $m = $month[$i];
    $y = $year[$i];

    // Create DateTime object
    $birthdate = new DateTime($y.'-'.$m.'-'.$d);
    // Calculate difference between birthdate and now and get years
    $age[$i] = $birthdate->diff($now)->y;   
}

print_r($age);

Answer 4

Quick-test

    <?php

        $day        = array(30, 03);
        $month      = array(07, 12);
        $year       = array(1998, 1997);
        $arrAges    = array();
        $todayTime  = new DateTime();

        foreach($year as $ikey=>$y){
            $birthDate      = $y . '-' .  $month[$ikey] . '-' . $day[$ikey];
            $bdTime         = new DateTime($birthDate);
            $ageInterval    = $todayTime->diff($bdTime);
            $arrAges[]      = $ageInterval->y;
        }

        var_dump($arrAges);

如果日期存储在php中的数组中，如何计算年龄？

4 个答案: