Question

CODEa所：

Image imageChipsetName = new System.Drawing.Bitmap(photoWidth, photoHeight);

StringFormat strFormat = new StringFormat();
strFormat.Alignment = StringAlignment.Center;
strFormat.LineAlignment = StringAlignment.Center;

Graphics graphics = Graphics.FromImage(imageChipsetName);
graphics.DrawString(stringA + "\n",
                    new Font("Tahoma", 14, FontStyle.Underline), Brushes.Black,
                    new RectangleF(0, 0, photoWidth, photoHeight), strFormat);
graphics.DrawString( stringB,
                    new Font("Tahoma", 14), Brushes.Black,
                    new RectangleF(0, 0, photoWidth, photoHeight), strFormat);

CodeB：

Image imageChipsetName = new System.Drawing.Bitmap(photoWidth, photoHeight);

StringFormat strFormat = new StringFormat();
strFormat.Alignment = StringAlignment.Center;
strFormat.LineAlignment = StringAlignment.Center;

Graphics graphics = Graphics.FromImage(imageChipsetName);
graphics.DrawString(stringA + "\n"+stringB,
                    new Font("Tahoma", 14, FontStyle.Underline), Brushes.Black,
                    new RectangleF(0, 0, photoWidth, photoHeight), strFormat);

我需要在一个盒子里画2个字符串。具有下划线样式的StringA，而StringB不具有。

CodeB几乎实现了我的目标，但stringA和stringB共享相同的样式。所以我使用CodeA进行了测试，但是使用它的程序是两个字符串相互重叠。我可以知道

Answer 1

codeA的问题在于stringA和stringB都是在完全相同的位置绘制的。

graphics.DrawString将字符串转换为图像并将其打印在纸张上。＆＃34; \ n＆＃34;一旦字符串变成图像，它就没有任何意义。它不会被打印，也不会创建新的一行。事实上，没有＆＃34;线＆＃34;在纸上。只是形象。

你需要给stringB不同的位置。使用Graphics.MeasureString (String, Font)来衡量stringA的大小，然后根据结果调整stringB的位置。

Image imageChipsetName = new System.Drawing.Bitmap(photoWidth, photoHeight);

StringFormat strFormat = new StringFormat();
strFormat.Alignment = StringAlignment.Center;
strFormat.LineAlignment = StringAlignment.Center;
Font strFontA = new Font("Tahoma", 14, FontStyle.Underline);//Font used by stringA


Graphics graphics = Graphics.FromImage(imageChipsetName);
graphics.DrawString(stringA + "\n",
                    strFont_A, Brushes.Black,
                    new RectangleF(0, 0, photoWidth, photoHeight), strFormat);

SizeF stringSizeA = new SizeF();
stringSizeA = Graphics.MeasureString(stringA, strFont_A);//Measuring the size of stringA

graphics.DrawString(stringB,
                    new Font("Tahoma", 14), Brushes.Black,
                    new RectangleF(0, stringSizeA.Height, photoWidth, photoHeight - stringSizeA.Height), strFormat);

抽绳相互重叠？

1 个答案: