Question

我是angularjs的新手。我开发了一个jax-rs restapi应用程序，它使用过滤器接受或拒绝基本身份验证调用我已经在邮递员中测试了我的应用程序，它运行正常。如果我没有通过用户/传递进行基本身份验证，或者当用户/传递正确时一切正常时，我收到错误消息。我写了一个angularjs服务，调用$ http服务传入标头user / pass。如果用户/传递正常，则呼叫响应正确的数据，而如果用户/传递错误，我收到此错误消息

SyntaxError: Unexpected token u in JSON at position 0

而不是我在过滤器中写的自定义

Response unathourizedStatus = Response
        .status(Response.Status.UNAUTHORIZED)
        .entity("user cannot access the resource")
        .build();
requestContext.abortWith(unathourizedStatus);

这是我的角色服务

app.service("GeafimServiceBasicAuth", function($http, $base64) {
    var self = this;

    // Read all Registry Type
    self.getRegistryTypeBA = function(username, password) {

        console.log("service user " + username);
        console.log("service pass " + password);

        var auth = $base64.encode(username + ":" + password);
        // var headers = {"Authorization": "Basic " + auth};

        console.log("service auth " + auth);


        var promise = $http({
            method : 'GET',
            url : "webapi/basicauth/registrytype",
            headers : {
                "Authorization" : "Basic " + auth
            }
        }).then(function(response) {
            return response.data;
        });
        return promise;
    }

这是我调用服务的控制器

GeafimCtrlViewBA.$inject = [ "$http", "GeafimServiceBasicAuth" ];
function GeafimCtrlViewBA($http, GeafimServiceBasicAuth) {

    var vm = this;

    vm.error = false;
    vm.viewRegistryType = {};

    vm.getRegTypeBA = function(username, password) {
        // Get registry data using a Service with Basic Auth
        console.log("user " + username);
        console.log("pass " + password);
        GeafimServiceBasicAuth.getRegistryTypeBA(username, password).then(
                function(data) {
                    vm.viewRegistryType = data;
                }, function(err) {
                    console.log("error " + err)
                });
    }

当我写console.log时，我会在实体中写入消息，而不是语法错误

我该怎么做？

感谢

Answer 1

$http服务正在尝试JSON.parse邮件并收到错误消息。而是将类型指定为"text/plain"

Response unathourizedStatus = Response
    .status(Response.Status.UNAUTHORIZED)
    .type("text/plain")
    .entity("user cannot access the resource")
    .build();
requestContext.abortWith(unathourizedStatus);

$ http错误函数

1 个答案: