Question

我的nodejs函数中有以下代码。即使IF条件为真，我也没有为stringResponse变量更新值。

var fs = require('fs'), 
                byline = require('byline');
            var stream = fs.createReadStream('Solutionbank.csv');
            var stringResponse = "We found a similar issue.  ";
            stream = byline.createStream(stream);
            stream.on('data', function(line) {
              var csvLine = line.toString('utf8');
                  csvLine = csvLine.toLowerCase().trim();

              var msgText = subject.toLowerCase().trim();
              //console.log("email block",msgText);
              if(csvLine.indexOf(msgText) > -1) {
                var arr = line.toString('utf8').split(",");

                stringResponse = stringResponse + "Issue ID"+arr[0]+",Subject : "+arr[1]+", Resolution Comment:"+arr[2];
                console.log(stringResponse);

                }
            });

            console.log("stringResponse from email",stringResponse);

Answer 1

行：

console.log（＆＃34; stringResponse from email＆＃34;，stringResponse）;

是outsite on（＆＃39; data＆＃39;）回调函数，在设置stringResponse变量之前调用此行。把它放在回调函数的末尾（内部）。或者在流末尾调用的另一个回调函数中：

stream.on('data', function(line) {
  ...
  console.log("stringResponse from email",stringResponse); // show each append 
});

  stream.on('end', function() {
  ...
  console.log("stringResponse from email",stringResponse); // show each append 
});

无法访问nodejs代码中的值

1 个答案: