Question

我想替换所有出现的字符串，但问题是我有一个删除单词和数组的数组。删除单词值。

例如：

var string = "this is a string to replace. This string should be replaced using javascript";

var replaceArray = ["this","is","string","should","javascript"];

var replaceArrayValue = ["There","are","strings","have to","node.js"];

for (var i = replaceArray.length - 1; i >= 0; i--) {

    var finalAns = string.replace(replaceArray[i],replaceArrayValue[i]);
}

我期待像

这样的东西

There are strings to replace. There strings have to be replaced using node.js

我找到了一些解决方案，其中我得到了最佳解决方案here。但是我不能在/string/g中使用该字符串。我必须使用replaceArray[i]

Answer 1

如果您更喜欢修复方法，可以使用RegExp构造函数构建带变量的动态regexp，并确保只匹配包含带有单词边界的模式的整个单词。不要忘记转义文字模式，并在循环之前声明finalAns并使用string var内容进行初始化。

＆＃13;

var string = "this is string to replace. this string should replace using javascript";
var replaceArray = ["this","is","string","should","javascript"];
var replaceArrayValue = ["There","are","strings","have to","node.js"];
var finalAns = string;
for (var i = replaceArray.length - 1; i >= 0; i--) {
    finalAns = finalAns.replace(RegExp("\\b" + replaceArray[i].replace(/[-\/\\^$*+?.()|[\]{}]/g, '\\$&') + "\\b", "g"), replaceArrayValue[i]);
}
console.log(finalAns);

＆＃13;

请注意，使用单个静态正则表达式的Roman's approach似乎对当前任务最有效（不需要每次都动态生成regexp）。

Answer 2

使用替换功能使用以下方法：

＆＃13;

var string = "this is string to replace. this string should replace using javascript",
    replaced = string.replace(/\b\w+\b/g, function ($m) {
        var search = ["this","is","string","should","javascript"],
            replacement = ["There","are","strings","have to","node.js"],
            key = search.indexOf($m);

        return (key !== -1)? replacement[key] : $m;
    });

console.log(replaced);

＆＃13;

来自＆＃34; 高性能JavaScript ＆＃34; （尼古拉斯扎卡斯）：

＆＃34; ...关于超出范围的变量：存储任何常用的变量局部变量中超出范围的变量，然后访问本地变量变量直接。＆＃34;

Answer 3

没有常规Exp

只能在循环中设置变量 string =finalAns;。因为每次循环设置旧字符串然后发生问题，

var string = "this is string to replace. this string should replace using javascript";

var replaceArray = ["this","is","string","should","javascript"];

var replaceArrayValue = ["There","are","strings","have to","node.js"];
alert(replaceArray.length);
for (var i = replaceArray.length - 1 ; i >= 0; i--) {

    var finalAns = string.replace(replaceArray[i],replaceArrayValue[i]);
    string =finalAns;
}
alert(finalAns);

Snippet Exmaple

＆＃13;

var string = "this is string to replace. this string should replace using javascript";

var replaceArray = ["this","is","string","should","javascript"];

var replaceArrayValue = ["There","are","strings","have to","node.js"];

for (var i = replaceArray.length - 1 ; i >= 0; i--) {

    var finalAns = string.replace(replaceArray[i],replaceArrayValue[i]);
    string =finalAns;
}
alert(finalAns);

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

＆＃13;

Answer 4

我使用声明式方法找到了一个解决方案：

const string = 'boo and Boo2'
const dictionary = { boo: 'faa', boo2: 'faa2' }
return string.split(' ')
  .map(word => dictionary[word.toLowerCase()] ?? word)
  .join(' ')
// 'faa and faa2'

javascript字符串替换为数组值的所有出现

4 个答案: