Question

我的Json响应如下所示，并且混淆了如何使用GSON解析它。请查看以下内容并指导我如何使用GSON解析它。

{
  "GetMICSDataResult": {
    "CONVERTIONFACT": [
{
        "CONVERSIONFACT": "1",
        "ITEMNO": "S1300W",
        "UOM": "Ea."
      },
      {
        "CONVERSIONFACT": "1",
        "ITEMNO": "S1300Y",
        "UOM": "Ea."
      }
    ],
ITEMDETAILS": [
      {
        "ITEMDESC": "FluorescentDeskLamp",
        "ITEMNO": "A11030",
        "LOCATION": "1",
        "PRICELIST": "WHS",
        "QTYONHAND": 164,
        "UNITPRICE": 38.3,
        "UOM": "Ea."
      },
      {
        "ITEMDESC": "FluorescentDeskLamp",
        "ITEMNO": "A11030",
        "LOCATION": "2",
        "PRICELIST": "WHS",
        "QTYONHAND": 247,
        "UNITPRICE": 38.3,
        "UOM": "Ea."
      }
]

} }

Answer 1

Gson gson = new Gson();
YourClass class = gson.fromJson(jsonInString, YourClass.class);

Answer 2

有很简单的方法可以做到这一点。只需使用POJO生成器http://www.jsonschema2pojo.org/，它将为您提供带有必要注释的普通对象。您也可以使用Json格式化程序来验证您的json https://jsonformatter.curiousconcept.com/ - 您发布的JSON无效。

如何使用GSON解析JSON

2 个答案: