Android编辑文本光标位置不会在第一次更改

Question

我想在点击EditText

之后更改final EditText editText = (EditText) findViewById(R.id.editText); editText.setText(text1 + text2); editText.setSelection(text1.length()); editText.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View view) { editText.setSelection(editText.getText().length() - text2.length()); } }); editText.addTextChangedListener(new TextWatcher() { @Override public void beforeTextChanged(CharSequence s, int start, int before, int count) { } @Override public void onTextChanged(CharSequence s, int start, int count, int after) { } @Override public void afterTextChanged(Editable editable) { if (!editable.toString().contains(text1) || !editable.toString().contains(text2)) { editText.setText(text1 + text2); editText.setSelection(text1.length()); } } }); } 中的光标位置

我希望点击后将位置光标更改为十到十二点之间，点击第一次。

这是我的代码：

 public Organization findAndModifyOrganization(Integer orgId, String name, Integer empId)
{
    Query query = new Query();
    query.addCriteria(Criteria.where("employees.id").is(empId));
    query.addCriteria(Criteria.where("id").is(orgId));

    Update update = new Update();
    update.set("employees.$.name", name);
    Organization org = mongoTemplate.findAndModify(query, update, new FindAndModifyOptions().returnNew(true), Organization.class);

    return org;
} 

Answer 1

如果我保持简单，下面的代码就足以实现你想要的（显然）

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.0/jquery.min.js"></script>

<table>
  <tr id="row">
    <td> This is td </td>
    <td> This is td2 </td>
  </tr>
</table>

<div id="subpage"> </div>

更新1

如果它是第一个获得焦点的EditText，上面的代码可以正常工作，否则，如果软键盘已经打开，则首先在轻敲的位置显示光标。这是解决这个问题的方法（不是最好的解决方案，但它会对你有用）

final EditText editText = (EditText) findViewById(R.id.editText);
editText.setText(text1 + text2);
// Keep it simple for the selection, it will place the cursor at end of text1
editText.setSelection(text1.length());
// editText.setCursorVisible(true); // I don't think it is required

// You don't need to go for OnTouchListener, OnClickListener will do for you
editText.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View view) {
        editText.setSelection(editText.getText().length() - text2.length());
    }
});

editText.addTextChangedListener(new TextWatcher() {
    @Override
    public void beforeTextChanged(CharSequence s, int start, int before, int count) {
    }

    @Override
    public void onTextChanged(CharSequence s, int start, int count, int after) {
    }

    @Override
    public void afterTextChanged(Editable editable) {
        if (!editable.toString().contains(text1) || !editable.toString().contains(text2)) {
            editText.setText(text1 + text2);
            editText.setSelection(text1.length());
        }
    }
});

Answer 2

使用应该使用android：imeOptions =＆＃34; actionNext＆＃34;在你的xml EditText中。这对你有帮助。

Answer 3

我不确定请尝试

editText.setText(text1 + text2);
editText.setSelection(editText.getText().length() - text2.length());
editText.setOnTouchListener(new View.OnTouchListener() {
         @Override
         public boolean onTouch(View view, MotionEvent motionEvent) {
           (EditText)view.setSelection((EditText)view.getText().length() - text2.length());
           return false;
         }
      });

Answer 4

而不是Selection.setSelection使用editText.setSelection（）