Question

我有这个输出

[u'JACK', u'', u'ROSE', u'', u'JANE']

我想从列表的每个元素中删除unicode，并将它们连接成一个单独的字符串：

输出：

['JACK ROSE JANE']

Answer 1

Previous answers are perfect. Just to show you another way:

result = [str(' '.join(filter(None, [u'JACK', u'', u'ROSE', u'', u'JANE'])))]

That's how to do it in functional paradigm :) And it looks nice, huh?

Actually, you don't need to worry about 'u' prefix. It simply let's you(as a developer) know that string is represented as unicode. I've added "str" to hide it(convert to ascii string) but it doesn't really needed. Please check this answer: What does the 'u' symbol mean in front of string values?

Answer 2

有很多方法可以对它进行编程。我更喜欢这个：

output = str(" ".join(filter(None,[u'JACK', u'', u'ROSE', u'', u'JANE'])))

如果您需要清单：

output = [str(" ".join(filter(None,[u'JACK', u'', u'ROSE', u'', u'JANE'])))]

Answer 3

在Python 2中，使用str函数将unicode字符串转换为普通字符串：

>>> unicodeString = u'stuff'
>>> normalString = str(unicodeString)
>>> print(unicodeString)
u'stuff'
>>> print(normalString)
'stuff'

Answer 4

>>> in_list = list(filter(lambda x: len(x)>0, [u'JACK', u'', u'ROSE', u'', u'JANE']))
>>> output = " ".join(in_list)                                                                   
>>> output
'JACK ROSE JANE'

Answer 5

仅为了简单起见：

position

在python2.7和python3.5中测试

Answer 6

通过在filter（）调用中使用None，它会删除所有的falsy元素。已经是@Andrey

a = [u'JACK', u'', u'ROSE', u'', u'JANE']

c = [str(' '.join(filter(None, a)))]
print (c)

或迭代并只得到True项，这里的反对论证是字符串运算符的可能性，o.lower，o.upper .....

b = [' '.join([o for o in a if o])]
print (b)

加入字符串列表并删除Unicode前缀

6 个答案: