将Int64转换为UUID

Question

如何将swift的Int64转换为UUID并返回？由于UUID是128位，我想用零填充前64位。

我可以UUID uuid_t来构建UInt8 Int64，这是{{1}}的元组，通过移动和投射{{1}}八次。

有更好的方法吗？

Answer 1

严格回答您的问题

最简单的＆＃34;这样做的方式（不依赖于CollectionType或Tuple的内存布局，并且不需要NSUUID）是：

extension UUID {
    init(number: Int64) {
        var number = number
        let numberData = Data(bytes: &number, count: MemoryLayout<Int64>.size)

        let bytes = [UInt8](numberData)

        let tuple: uuid_t = (0, 0, 0, 0, 0, 0, 0, 0,
                             bytes[0], bytes[1], bytes[2], bytes[3],
                             bytes[4], bytes[5], bytes[6], bytes[7])

        self.init(uuid: tuple)
    }

    var intValue: Int64? {
        let tuple = self.uuid
        guard tuple.0 == 0 && tuple.1 == 0 && tuple.2 == 0 && tuple.3 == 0 &&
              tuple.4 == 0 && tuple.5 == 0 && tuple.6 == 0 && tuple.7 == 0 else {
                return nil
        }

        let bytes: [UInt8] = [tuple.8, tuple.9, tuple.10, tuple.11,
                              tuple.12, tuple.13, tuple.14, tuple.15]

        let numberData = Data(bytes: bytes)

        let number = numberData.withUnsafeBytes { $0.pointee } as Int64

        return number
    }
}

此外，您可能需要throw / fatalError而不是返回nil。

创建有效的UUID s

为了完成（并且实际上可以创建有效的UUID），我添加了一种从2 Int64创建它的方法，并使用它重写了您的问题的答案：

来自UUID 的

(Int64, Int64)创建

extension UUID {
    init(numbers: (Int64, Int64)) {
        var firstNumber = numbers.0
        var secondNumber = numbers.1
        let firstData = Data(bytes: &firstNumber, count: MemoryLayout<Int64>.size)
        let secondData = Data(bytes: &secondNumber, count: MemoryLayout<Int64>.size)

        let bytes = [UInt8](firstData) + [UInt8](secondData)

        let tuple: uuid_t = (bytes[0], bytes[1], bytes[2], bytes[3],
                             bytes[4], bytes[5], bytes[6], bytes[7],
                             bytes[8], bytes[9], bytes[10], bytes[11],
                             bytes[12], bytes[13], bytes[14], bytes[15])

        self.init(uuid: tuple)
    }

    var intTupleValue: (Int64, Int64) {
        let tuple = self.uuid

        let firstBytes: [UInt8] = [tuple.0, tuple.1, tuple.2, tuple.3,
                                   tuple.4, tuple.5, tuple.6, tuple.7]

        let secondBytes: [UInt8] = [tuple.8, tuple.9, tuple.10, tuple.11,
                                    tuple.12, tuple.13, tuple.14, tuple.15]

        let firstData = Data(bytes: firstBytes)
        let secondData = Data(bytes: secondBytes)

        let first = firstData.withUnsafeBytes { $0.pointee } as Int64
        let second = secondData.withUnsafeBytes { $0.pointee } as Int64

        return (first, second)
    }
}

从UUID创建

Int64（填充MSB为0）

extension UUID {
    init(number: Int64) {
        self.init(numbers: (0, number))
    }

    var intValue: Int64? {
        let (first, second) = intTupleValue
        guard first == 0 else { return nil }

        return second
    }
}

Answer 2

UUID是基础类型NSUUID的Swift叠加层类型， 后者可以从字节缓冲区创建。一点点 指针杂乱的工具也适用于64位整数：

let vals: [UInt64] = [0, 0x123456789abcdef]

let uuid = vals.withUnsafeBufferPointer {
    $0.baseAddress!.withMemoryRebound(to: UInt8.self, capacity: 16) {
         NSUUID(uuidBytes: $0) as UUID
    }
}

print(uuid) // 00000000-0000-0000-EFCD-AB8967452301