我尝试用BioPython,Phylo模块构建一棵树 到目前为止我所做的是这张图片:
每个名称都有一个四位数字后跟 - 和一个数字:这个数字表示该序列的表示次数。这意味着1578 - 22,该节点应代表22个序列。
所以现在我知道如何更改节点的每个大小。每个节点都有不同的大小,这很容易做一个不同值的数组:
fh = open(MEDIA_ROOT + "groupsnp.txt")
list_size = {}
for line in fh:
if '>' in line:
labels = line.split('>')
label = labels[-1]
label = label.split()
num = line.split('-')
size = num[-1]
size = size.split()
for lab in label:
for number in size:
list_size[lab] = int(number)
a = array(list_size.values())
但是数组是任意的,我想将正确的节点大小放入正确的节点,我试过这个:
for elem in list_size.keys():
if labels == elem:
Phylo.draw_graphviz(tree_xml, prog="neato", node_size=a)
但是当我使用if语句时没有出现。
无论如何这样做?
我真的很感激!
谢谢大家
答案 0 :(得分:8)
我终于有了这个工作。基本前提是您将使用labels/nodelist
来构建node_sizes
。这样他们就能恰当地联系起来。我确定我缺少一些重要的选项,使树看起来100%,但似乎节点大小正确显示。
#basically a stripped down rewrite of Phylo.draw_graphviz
import networkx, pylab
from Bio import Phylo
#taken from draw_graphviz
def get_label_mapping(G, selection):
for node in G.nodes():
if (selection is None) or (node in selection):
try:
label = str(node)
if label not in (None, node.__class__.__name__):
yield (node, label)
except (LookupError, AttributeError, ValueError):
pass
kwargs={}
tree = Phylo.read('tree.dnd', 'newick')
G = Phylo.to_networkx(tree)
Gi = networkx.convert_node_labels_to_integers(G, discard_old_labels=False)
node_sizes = []
labels = dict(get_label_mapping(G, None))
kwargs['nodelist'] = labels.keys()
#create our node sizes based on our labels because the labels are used for the node_list
#this way they should be correct
for label in labels.keys():
if str(label) != "Clade":
num = label.name.split('-')
#the times 50 is just a guess on what would look best
size = int(num[-1]) * 50
node_sizes.append(size)
kwargs['node_size'] = node_sizes
posi = networkx.pygraphviz_layout(Gi, 'neato', args='')
posn = dict((n, posi[Gi.node_labels[n]]) for n in G)
networkx.draw(G, posn, labels=labels, node_color='#c0deff', **kwargs)
pylab.show()
结果树