Question

我有这样的样本数据

DECLARE @T Table (ID INT,Name VARCHAR(10),DOB DATE)
INSERT INTO @T (ID,Name,DOB) VALUES (1,'Mohan','2016-11-13')
INSERT INTO @T (ID,Name,DOB) VALUES (6,'Manasa','2016-11-10')
INSERT INTO @T (ID,Name,DOB) VALUES (2,'Raj','2016-11-07')
INSERT INTO @T (ID,Name,DOB) VALUES (3,'Manny','2016-10-30')
INSERT INTO @T (ID,Name,DOB) VALUES (4,'kamal','2016-11-01')
INSERT INTO @T (ID,Name,DOB) VALUES (5,'Raj','2016-11-08')

查询：

SELECT * from @T WHERE 
DOB >= DATEADD(wk, DATEDIFF(wk,0,GETDATE()), -1) 
AND DOB <= DATEADD(wk, DATEDIFF(wk,0,GETDATE()), 5)

我在星期一到今天无法到达今天的日期意味着2016-11-10.I＆＃39; m涵盖本周即将到来的所有日期。

我想获得这样的数据

ID  Name    DOB
6   Manasa  2016-11-10
5   Raj     2016-11-08

建议我最好的方式

Answer 1

DATENAME（）将解决您的问题。

DECLARE @T Table (ID INT,Name VARCHAR(10),DOB DATE)
INSERT INTO @T (ID,Name,DOB) VALUES (1,'Mohan','2016-11-13')
INSERT INTO @T (ID,Name,DOB) VALUES (6,'Manasa','2016-11-10')
INSERT INTO @T (ID,Name,DOB) VALUES (2,'Raj','2016-11-07')
INSERT INTO @T (ID,Name,DOB) VALUES (3,'Manny','2016-10-30')
INSERT INTO @T (ID,Name,DOB) VALUES (4,'kamal','2016-11-01')
INSERT INTO @T (ID,Name,DOB) VALUES (5,'Raj','2016-11-08')

SELECT * from @T 
WHERE DATENAME(WEEK,DOB) = DATENAME(WEEK,GETDATE())
GO

Answer 2

DECLARE @StartDate DATE = DATEADD(wk, DATEDIFF(wk,0,GETDATE()), 0),@EndDate DATE = GETDATE() SELECT * FROM @T WHERE DATEDIFF(DAY,DOB,@StartDate) <= 0 AND DATEDIFF(DAY,DOB,@EndDate) >= 0

Answer 3

试试这个

DECLARE @T Table (ID INT,Name VARCHAR(10),DOB DATE)
INSERT INTO @T (ID,Name,DOB) VALUES (1,'Mohan','2016-11-13')
INSERT INTO @T (ID,Name,DOB) VALUES (6,'Manasa','2016-11-10')
INSERT INTO @T (ID,Name,DOB) VALUES (2,'Raj','2016-11-07')
INSERT INTO @T (ID,Name,DOB) VALUES (3,'Manny','2016-10-30')
INSERT INTO @T (ID,Name,DOB) VALUES (4,'kamal','2016-11-01')
INSERT INTO @T (ID,Name,DOB) VALUES (5,'Raj','2016-11-08')


SELECT * from @T WHERE 
DOB >= DATEADD(wk, DATEDIFF(wk,0,GETDATE()), 0)
AND DOB <= DATEADD(wk, 0,GETDATE());

这给了我正确的结果。

如何从星期一到今天的数据获取数据

3 个答案: