如果在数据库中找到的项目超过10个，我正在尝试将搜索结果分页。出于某种原因，即使代码识别出有超过10个项目并为后续页面创建链接，所有搜索结果仅列在第一页上。有人能帮忙吗？代码如下：
for($i = 0; $i < $terms_count; $i++)
{
$search_terms_array[$i] = trim($search_terms_array[$i]);
${"query".$i} = $this->mysqli_link->query("SELECT prod_id, prod_tags FROM table WHERE prod_tags LIKE '%" . $search_terms_array[$i] . "%'");
if(${"query".$i}->num_rows < 1)
{
$zerocount++;
}
else
{
$rows = array();
while($row = ${"query".$i}->fetch_array())
{
$rows[] = $row;
}
foreach($rows as $row)
{
$search_id_results[] = $row['prod_id'];
}
}
}
if($zerocount == $terms_count)
{
echo $this->err_handle->fetch_error_text("search_terms_0_results");
return;
}
else
{
$search_results = array_values(array_unique($search_id_results));
$search_results_count = count($search_results);
$search_page_count = ceil($search_results_count / 10);
$search_page_first_result = ($search_page - 1) * 10;
echo '<p>Go to page: ';
for($i = 1; $i <= $search_page_count; $i++)
{
if($i == $search_page)
{
echo " <strong>" . $i . "</strong>";
}
else
{
echo ' <a href="index.php?section=products&action=search&page=' . $i . '">' . $i . '</a>';
}
}
echo '</p><p> </p><p> </p>';
for($i = 0; $i < $search_results_count; $i++)
{
$query = $this->mysqli_link->query("SELECT * FROM table WHERE prod_id='" . $search_results[$i] . "' LIMIT " . $search_page_first_result . ", 10");
while($row = $query->fetch_array())
{
echo "<h4><a href=\"index.php?section=products&subsection=" . $row['prod_category'] . "&prodid=" . $row['prod_id'] . "\">" . $row['prod_name'] . "</h4></a><p><img src=\"includes/images/product_images/" . $row['prod_category'] . "/" . $row['prod_pic_filename'] . "\" alt=\"\" width=\"150\" height=\"200\" /></p><p>Price: £" . $row['prod_price'] . "</p><p>" . $row['prod_code'] . "</p><input type=\"number\" name=\"prod_qty\" maxlength=\"2\" /><input type=\"submit\" name=\"add_to_basket\" value=\"Add To Basket\" /></form></p><p> </p><p> </p>";
}
}
echo '<p>Go to page: ';
for($i = 1; $i <= $search_page_count; $i++)
{
if($i == $search_page)
{
echo " <strong>" . $i . "</strong>";
}
else
{
echo ' <a href="index.php?section=products&action=search&page=' . $i . '">' . $i . '</a>';
}
}
echo '</p><p> </p><p> </p>';
}
答案 0 :(得分：0)
好的，我找到了解决这个问题的方法，现在完整的功能如下：
public function product_search($search_terms, $search_page, $search_flag_check)
{
if($search_flag_check == "invalid")
{
echo $this->err_handle->fetch_error_text("invalid_ns_term");
return;
}
if($search_terms == "")
{
echo $this->err_handle->fetch_error_text("no_search_string");
return;
}
$search_terms = htmlspecialchars($search_terms);
$search_terms = $this->mysqli_link->real_escape_string(filter_var($search_terms, FILTER_SANITIZE_FULL_SPECIAL_CHARS, FILTER_FLAG_NO_ENCODE_QUOTES));
$search_terms_array = explode(" ", $search_terms);
$terms_count = count($search_terms_array);
$zerocount = 0;
$search_id_results = array();
for($i = 0; $i < $terms_count; $i++)
{
$search_terms_array[$i] = trim($search_terms_array[$i]);
${"query".$i} = $this->mysqli_link->query("SELECT prod_id, prod_tags FROM table WHERE prod_tags LIKE '%" . $search_terms_array[$i] . "%'");
if(${"query".$i}->num_rows < 1)
{
$zerocount++;
}
else
{
$rows = array();
while($row = ${"query".$i}->fetch_array())
{
$rows[] = $row;
}
foreach($rows as $row)
{
$search_id_results[] = $row['prod_id'];
}
}
}
if($zerocount == $terms_count)
{
echo $this->err_handle->fetch_error_text("search_terms_0_results");
return;
}
else
{
$search_results = array_values(array_unique($search_id_results));
$search_results_count = count($search_results);
$search_page_count = ceil($search_results_count / 10);
$search_page_first_result = ($search_page - 1) * 10;
$search_page_results_limit = 10;
if($search_page_first_result < 1)
{
$search_page_first_result = 1;
}
echo '<p>Go to page: ';
for($i = 1; $i <= $search_page_count; $i++)
{
if($i == $search_page)
{
echo " <strong>" . $i . "</strong>";
}
else
{
echo ' <a href="index.php?section=products&action=search&page=' . $i . '">' . $i . '</a>';
}
}
echo '</p><p> </p><p> </p>';
$search_page_upper_limit = $search_page_first_result + 9;
if(array_key_exists($search_page_upper_limit, $search_results))
{
$search_results_limit = $search_page_first_result + $search_page_results_limit;
}
else
{
end($search_results);
$search_results_limit = key($search_results);
reset($search_results);
}
for($i = $search_page_first_result; $i <= $search_results_limit; $i++)
{
$query2 = $this->mysqli_link->query("SELECT * FROM table WHERE prod_id='" . $search_results[$i] . "'");
$row = $query2->fetch_array();
echo "<h4><a href=\"index.php?section=products&subsection=" . $row['prod_category'] . "&prodid=" . $row['prod_id'] . "\">" . $row['prod_name'] . "</h4></a><p><img src=\"includes/images/product_images/" . $row['prod_category'] . "/" . $row['prod_pic_filename'] . "\" alt=\"\" width=\"150\" height=\"200\" /></p><p>Price: £" . $row['prod_price'] . "</p><p>" . $row['prod_code'] . "</p><input type=\"number\" name=\"prod_qty\" maxlength=\"2\" /><input type=\"submit\" name=\"add_to_basket\" value=\"Add To Basket\" /></form></p><p> </p><p> </p>";
}
echo '<p>Go to page: ';
for($i = 1; $i <= $search_page_count; $i++)
{
if($i == $search_page)
{
echo " <strong>" . $i . "</strong>";
}
else
{
echo ' <a href="index.php?section=products&action=search&page=' . $i . '">' . $i . '</a>';
}
}
echo '</p><p> </p><p> </p>';
}
}
我花了一点思考，我即将放弃，但后来我考虑使用数组键来计算每个搜索页面的限制，并在相关的PHP数组函数上进行一些谷歌搜索后，它们全部落到了位置很好。 我知道代码现在可能不是很整洁，可能有一些方法可以优化/改进它，但是暂时它可以完成这项任务。