Question

一直在摸不着头脑，但我觉得我忽略了明显的答案，我的搜索词都没有导致任何结果。我正在编制一个数据库中的调查结果，如下结构

ID  TestName     Q1    Q2    Q3    Q4
--  ---------  ----  ----  ----  ----
1   test1        1     2     1     1
2   test1        2     3     4     1
3   test2        1     1     4     2
4   test1        2     5     3     4
5   test2        1     5     2     4

我想在每列中对相似的结果进行分组，只要它们共享相同的名称，并从每个相似的结果中获取计数。我的最终输出如下所示，但我试图找出如何在不进行4次单独查询的情况下编写查询。

Test 1
        Question 1 Results
        1(1)
        2(2)
        3(0)
        4(0)
        5(0)

        Question 2 Results
        1(0)
        2(1)
        3(1)
        4(0)
        5(1)

        Question 3 Results
        1(1)
        2(0)
        3(1)
        4(1)
        5(0)

        Question 4 Results
        1(2)
        2(0)
        3(0)
        4(1)
        5(0)

Test 2
        Question 1 Results
        1(2)
        2(0)
        3(0)
        4(0)
        5(0)

        Question 2 Results
        1(1)
        2(0)
        3(0)
        4(0)
        5(1)

        Question 3 Results
        1(0)
        2(1)
        3(0)
        4(1)
        5(0)

        Question 4 Results
        1(0)
        2(1)
        3(0)
        4(1)
        5(0)

Answer 1

类似

select name, sum(q1), sum(q2), sum(q3), sum(q4)
from tbl
group by name

如果您将q值存储为varchar，则可以在对它们求和之前将它们转换为数字：

sum(cast(q1 as int))

Answer 2

declare @YourTable table (
    id int,
    TestName varchar(10),
    q1 char(1),
    q2 char(1),
    q3 char(1),
    q4 char(1)
)

insert into @YourTable
    (id, TestName, q1, q2, q3, q4)
    select 1,'test1','1','2','1','1' union all
    select 2,'test1','2','3','4','1' union all
    select 3,'test2','1','1','4','2' union all
    select 4,'test1','2','5','3','4' union all
    select 5,'test2','1','5','2','4'

select TestName, 
       sum(case when q1 = '1' then 1 else 0 end) as [q1(1)],
       sum(case when q1 = '2' then 1 else 0 end) as [q1(2)],
       /* ... */
       sum(case when q4 = '4' then 1 else 0 end) as [q4(4)],      
       sum(case when q4 = '5' then 1 else 0 end) as [q4(5)]
    from @YourTable
    group by TestName

在SQLServer中创建多个数据组

2 个答案: