我的代码是
$url = "URL";
$curl = curl_init();
curl_setopt_array($curl, array(
CURLOPT_URL => $url,
CURLOPT_RETURNTRANSFER => 1
));
$result = curl_exec($curl);
var_dump($result);
$json = json_decode($result);
print_r($json);
curl_close($curl);
来自 var_dump($ result)的回复是 -
string(1866) "{"status":true,"result":[{"time":"2016-11-15T19:20:27.000Z"},{"time":"2016-11-15T19:18:15.000Z"},{"time":"2016-11-15T19:15:03.000Z"},
我从 print_r($ json)得到的回复是 -
stdClass Object
(
[status] => 1
[result] => Array
(
[0] => stdClass Object
(
[time] => 2016-11-15T19:20:27.000Z
)
[1] => stdClass Object
(
[time] => 2016-11-15T19:18:15.000Z
)
[2] => stdClass Object
(
[time] => 2016-11-15T19:15:03.000Z
)
我需要将时间值转换为某个变量。
我在Javscript中做过的事情是 -
var response = JSON.parse(xmlHttpSerie.responseText);
response.forEach(function(items)
{
currentTime = items.time;
}
有谁能告诉我如何从变量的响应中获取时间值?
答案 0 :(得分:1)
echo $json['result'][0]['time'];
在对原始问题进行重大更改后编辑:
您需要使用json_decode()
的第二个参数将对象转换为关联数组。然后,您可以使用foreach()
循环遍历数组和打印时间:
$json = json_decode($result, TRUE);
foreach ($json['result'] as $index => $v) {
echo $v['time'].'<br>';
}