您可以在数据库迁移文件中的列之间复制/移动数据吗?

时间:2016-11-16 00:59:07

标签: python sqlalchemy flask-sqlalchemy database-migration flask-migrate

我有一个SqlAlchemy / Flask应用程序。在其中,我有一个名为MyModelA的现有模型。这就是它的样子:

class MyModelA(db.Model):
    a_id   = db.Column(db.Integer, nullable=False, primary_key=True)
    my_field1 = db.Column(db.String(1024), nullable=True)

现在,我正在添加一个子模型MyModelB。这就是它的样子:

class MyModelB(db.Model):
    b_id   = db.Column(db.Integer, nullable=False, primary_key=True)
    a_id = db.Column(db.Integer, db.ForeignKey(MyModelA.a_id), nullable=False)
    my_field2 = db.Column(db.String(1024), nullable=True)

然后我跑python manage.py migrate。这是迁移文件中显示的内容:

def upgrade():
    op.create_table('my_model_b',
    sa.Column('b_id', sa.Integer(), nullable=False),
    sa.Column('a_id', sa.Integer(), nullable=False),
    sa.Column('my_field2', sa.String(length=1024), nullable=True),
    sa.ForeignKeyConstraint(['a_id'], [u'my_model_a.a_id'], ),
    sa.PrimaryKeyConstraint('b_id')
    )

def downgrade():
    op.drop_table('my_table_b')

我想编辑此迁移,以便为MyModelA的每个实例编辑它,应创建实例MyModelB的子记录,并将MyModelB.my_field2设置为MyModelA.my_field1。我该怎么办?

请显示升级和降级的代码。

1 个答案:

答案 0 :(得分:1)

修改

您可以为一次性迁移执行类似的操作:

db.engine.execute("INSERT INTO model_b (a_id) select a_id from model_a");

如果你真的想要sqlalschemy代码:

for model in db.query(ModelA).all()
    db.session.add(ModelB(a_id=model.id))
db.session.commit()

上一个回答:

您所描述的内容并非您通常在迁移中执行的操作。迁移更改/创建数据库的结构。如果每次创建新的MyModelA时都需要它,这听起来更像是事件:http://docs.sqlalchemy.org/en/latest/orm/events.html#session-events

class MyModelA(db.Model):
    ...


@sqlalchemy.event.listens_for(SignallingSession, 'before_flush')
def insert_model_b(session, transaction, instances):
    for instance in session.new:
        if isinstance(instance, MyModelA):
            model_b = MyModelB(a=instance)
            session.add(model_b)

此外,您的架构需要显示该关系(而不仅仅是外键),因此您可以将尚未插入的model_a分配给model_b.a:

class MyModelB(db.Model):
    b_id   = db.Column(db.Integer, nullable=False, primary_key=True)
    a_id = db.Column(db.Integer, db.ForeignKey(MyModelA.a_id), nullable=False)
    a = relationship("MyModelA")
    my_field2 = db.Column(db.String(1024), nullable=True)

完整代码示例:

import sqlalchemy
from sqlalchemy.orm import relationship
from flask import Flask
from flask.ext.sqlalchemy import SQLAlchemy
from flask.ext.sqlalchemy import SignallingSession

app = Flask(__name__)
app.config['SQLALCHEMY_DATABASE_URI'] = 'sqlite:///:memory:'
app.config['SQLALCHEMY_ECHO'] = True

db = SQLAlchemy(app)

class MyModelA(db.Model):
    __tablename__ = 'model_a'
    a_id = db.Column(db.Integer, nullable=False, primary_key=True)
    my_field1 = db.Column(db.String(1024), nullable=True)

class MyModelB(db.Model):
    __tablename__ = 'model_b'

    b_id = db.Column(db.Integer, nullable=False, primary_key=True)
    a_id = db.Column(db.Integer, db.ForeignKey(MyModelA.a_id), nullable=False)
    a = relationship(MyModelA)
    my_field2 = db.Column(db.String(1024), nullable=True)


@sqlalchemy.event.listens_for(SignallingSession, 'before_flush')
def insert_model_b(session, transaction, instances):
    for instance in session.new:
        if isinstance(instance, MyModelA):
            model_b = MyModelB(a=instance)
            session.add(model_b)

db.create_all()
model_a = MyModelA()
db.session.add(model_a)
db.session.commit()