Question

这对我的同事MongoDB和NodeJs Devs来说是一个挑战

我有一个搜索表单，用户可以在其中输入以下内容：

225/65R16 71T K715 Hankook

至于我的mongodb，我有一个包含以下文档的集合：

1- { _id: SomeId, Description: 225/65R16 71T K715, Brand: Hankook, Ref: 123455 }
2- { _id: SomeId, Description: 225/65R16 71T K715, Brand: Continental, Ref: 123456 }
3- { _id: SomeId, Description: 225/65R16 94T Energy, Brand: Hankook, Ref: 123457 }

我该怎么做才能在搜索下面的任何组合时获得上述文档1和3的结果？

组合清单：

Hankook
225/65R16
225/65R16 Hankook
225 Hankook
225 Han

Answer 1

您可以尝试创建索引：

db.yourollection.createIndex({"Description":1,"Brand":1})

然后通过搜索值，例如：

mongoosemodel.find({$text:{$search: 225/65R16 Hankook}},{Description:1,Brand:1})

而且，如果您获得的结果超出预期，则可以使用Javascript进行过滤。

Answer 2

您可以使用regular expressions匹配字段的开头，然后使用OR operator。

假设以下文件。

{ "Description" : "225/65R16 71T K715", "Brand" : "Hankook", "Ref" : 123455 }
{ "Description" : "225/65R16 71T K715", "Brand" : "Continental", "Ref" : 123455 }
{ "Description" : "225/65R16 94T", "Brand" : "Hankook", "Ref" : 123455 }

以下查询会返回预期结果。

> db.test.find({$or: [{Description: {$regex: '^225/65R16'}, Brand: {$regex: '^Hankook'}}]})
{ "Description" : "225/65R16 71T K715", "Brand" : "Hankook", "Ref" : 123455 }
{"Description" : "225/65R16 94T", "Brand" : "Hankook", "Ref" : 123455 }

> db.test.find({$or: [{Description: {$regex: '^225'}, Brand: {$regex: '^Han'}}]})
{ "Description" : "225/65R16 71T K715", "Brand" : "Hankook", "Ref" : 123455 }
{ "Description" : "225/65R16 94T", "Brand" : "Hankook", "Ref" : 123455 }

对于225/65R16，虽然无法避免匹配文档编号2，但查询不包含足够的消歧信息。

Answer 3

这是一个基于node.js，javascript和猫鼬的示例

您可以在集合的多个字段中查找“搜索词”或“搜索词”，如下所示：

var searchTerm = 'Hankook'; // put your search term here

YourMongooseModel.find({ 
    $or: [
        // in this example we want to search at two fields 'Description' and 'Brand'
        // however you can put any fields as you desire
        {"Description": {$regex: searchTerm, $options: "i"}},
        {"Brand": {$regex: searchTerm, $options: "i"}}
    ]
}, function (err, docs) {
    if(docs) {
        // handle retreived docs here
    }
});

希望这会有所帮助。谢谢

Answer 4

使用聚合来连接搜索字段，然后只使用正则表达式：

// Build a regex from your string,
// Example : containing exactly all word, no order
enter code here
var a = "225/65R16 71T K715 Hankook"
var ar = a.split(new RegExp("\\s")); // [ '225/65R16', '71T', 'K715', 'Hankook' ]
var estr = ""
ar.forEach(function(e){ estr += "(?=.*\b"+e+"\b)";});
var re = new RegExp("^.*"+estr+".*$"); // /^.*(?=.*\b225\/65R16\b)(?=.*\b71T\b)(?=.*\bK715\b)(?=.*\bHankook\b).*$/



enter code here
db.a.aggregate([
   {
       $project:{
          st: {$concat:["$Brand"," ", "$Description"]}, 
         _id:1,
         Description:1,
         Brand:1,
         Ref:1
       }
   },
   {
      $match:{
         st: /^(?=.*\b225\/65R16\b)(?=.*\b71T\b)(?=.*\bK715\b)(?=.*\bHankook\b).*$/
      }
   }
])

// output { "_id" : ObjectId("582f009da52585177f054ddc"), "Description" : "225/65R16 71T K715", "Brand" : "Hankook", "Ref" : "123455", "st" : "Hankook 225/65R16 71T K715" }

MongoDB搜索匹配字符串部分的多个字段

4 个答案: