Question

我们如何将通过屏幕变量中心的javascript window.open功能打开的弹出窗口居中到当前所选的屏幕分辨率？

Answer 1

单/双监视器功能（归功于http://www.xtf.dk - 谢谢！）

更新：由于@Frost，它也适用于未达到屏幕宽度和高度的窗口！

如果你在双显示器上，窗口将水平居中，但不是垂直居中......使用此功能来解释它。

function PopupCenter(url, title, w, h) {
    // Fixes dual-screen position                         Most browsers      Firefox
    var dualScreenLeft = window.screenLeft != undefined ? window.screenLeft : window.screenX;
    var dualScreenTop = window.screenTop != undefined ? window.screenTop : window.screenY;

    var width = window.innerWidth ? window.innerWidth : document.documentElement.clientWidth ? document.documentElement.clientWidth : screen.width;
    var height = window.innerHeight ? window.innerHeight : document.documentElement.clientHeight ? document.documentElement.clientHeight : screen.height;

    var systemZoom = width / window.screen.availWidth;
var left = (width - w) / 2 / systemZoom + dualScreenLeft
var top = (height - h) / 2 / systemZoom + dualScreenTop
    var newWindow = window.open(url, title, 'scrollbars=yes, width=' + w / systemZoom + ', height=' + h / systemZoom + ', top=' + top + ', left=' + left);

    // Puts focus on the newWindow
    if (window.focus) newWindow.focus();
}

用法示例：

PopupCenter('http://www.xtf.dk','xtf','900','500');

CREDIT GOES TO：http://www.xtf.dk/2011/08/center-new-popup-window-even-on.html （我想直接链接到此页面，但万一这个网站出现故障，代码就在这里，欢呼！）

Answer 2

尝试这样：

function popupwindow(url, title, w, h) {
  var left = (screen.width/2)-(w/2);
  var top = (screen.height/2)-(h/2);
  return window.open(url, title, 'toolbar=no, location=no, directories=no, status=no, menubar=no, scrollbars=no, resizable=no, copyhistory=no, width='+w+', height='+h+', top='+top+', left='+left);
}

Answer 3

由于在多显示器设置中确定当前屏幕中心的复杂性，更容易的选择是将弹出窗口置于父窗口的中心。只需将父窗口作为另一个参数传递：

function popupwindow(url, title, win, w, h) {
    var y = win.top.outerHeight / 2 + win.top.screenY - ( h / 2)
    var x = win.top.outerWidth / 2 + win.top.screenX - ( w / 2)
    return win.open(url, title, 'toolbar=no, location=no, directories=no, status=no, menubar=no, scrollbars=no, resizable=no, copyhistory=no, width='+w+', height='+h+', top='+y+', left='+x);
}

Answer 4

来源：http://www.nigraphic.com/blog/java-script/how-open-new-window-popup-center-screen

function PopupCenter(pageURL, title,w,h) {
  var left = (screen.width/2)-(w/2);
  var top = (screen.height/2)-(h/2);
  var targetWin = window.open (pageURL, title, 'toolbar=no, location=no, directories=no, status=no, menubar=no, scrollbars=no, resizable=no, copyhistory=no, width='+w+', height='+h+', top='+top+', left='+left);
  return targetWin;
}

Answer 5

它在Firefox中运行良好只需将顶部变量更改为任何其他名称，然后重试

        var w = 200;
        var h = 200;
        var left = Number((screen.width/2)-(w/2));
        var tops = Number((screen.height/2)-(h/2));

window.open("templates/sales/index.php?go=new_sale", '', 'toolbar=no, location=no, directories=no, status=no, menubar=no, scrollbars=no, resizable=no, copyhistory=no, width='+w+', height='+h+', top='+tops+', left='+left);

Answer 6

如果你想把它放在你当前所在的框架上，我推荐这个功能：

function popupwindow(url, title, w, h) {
    var y = window.outerHeight / 2 + window.screenY - ( h / 2)
    var x = window.outerWidth / 2 + window.screenX - ( w / 2)
    return window.open(url, title, 'toolbar=no, location=no, directories=no, status=no, menubar=no, scrollbars=no, resizable=no, copyhistory=no, width=' + w + ', height=' + h + ', top=' + y + ', left=' + x);
}

类似于Crazy Tim的回答，但不使用window.top。这样，即使窗口嵌入来自不同域的iframe，它也会起作用。

Answer 7

我的建议是使用剩余空间的33％或25％的顶部位置，而不是这里发布的其他示例的50％，
主要是因为窗口标题，
使用者看起来更好，更舒适，

完整代码：

    <script language="javascript" type="text/javascript">
        function OpenPopupCenter(pageURL, title, w, h) {
            var left = (screen.width - w) / 2;
            var top = (screen.height - h) / 4;  // for 25% - devide by 4  |  for 33% - devide by 3
            var targetWin = window.open(pageURL, title, 'toolbar=no, location=no, directories=no, status=no, menubar=no, scrollbars=no, resizable=no, copyhistory=no, width=' + w + ', height=' + h + ', top=' + top + ', left=' + left);
        } 
    </script>
</head>
<body>
    <button onclick="OpenPopupCenter('http://www.google.com', 'TEST!?', 800, 600);">click on me</button>
</body>
</html>

看看这一行：
var top =（screen.height - h）/ 4; //为25％ - 偏离4 |为33％ - 偏离3

Answer 8

您可以使用css来执行此操作，只需将以下属性提供给要放置在弹出窗口中心的元素

element{

position:fixed;
left: 50%;
top: 50%;
-ms-transform: translate(-50%,-50%);
-moz-transform:translate(-50%,-50%);
-webkit-transform: translate(-50%,-50%);
 transform: translate(-50%,-50%);

}

Answer 9

Facebook使用以下算法来定位他们的登录弹出窗口：

function PopupCenter(url, title, w, h) {
  var userAgent = navigator.userAgent,
      mobile = function() {
        return /\b(iPhone|iP[ao]d)/.test(userAgent) ||
          /\b(iP[ao]d)/.test(userAgent) ||
          /Android/i.test(userAgent) ||
          /Mobile/i.test(userAgent);
      },
      screenX = typeof window.screenX != 'undefined' ? window.screenX : window.screenLeft,
      screenY = typeof window.screenY != 'undefined' ? window.screenY : window.screenTop,
      outerWidth = typeof window.outerWidth != 'undefined' ? window.outerWidth : document.documentElement.clientWidth,
      outerHeight = typeof window.outerHeight != 'undefined' ? window.outerHeight : document.documentElement.clientHeight - 22,
      targetWidth = mobile() ? null : w,
      targetHeight = mobile() ? null : h,
      V = screenX < 0 ? window.screen.width + screenX : screenX,
      left = parseInt(V + (outerWidth - targetWidth) / 2, 10),
      right = parseInt(screenY + (outerHeight - targetHeight) / 2.5, 10),
      features = [];
  if (targetWidth !== null) {
    features.push('width=' + targetWidth);
  }
  if (targetHeight !== null) {
    features.push('height=' + targetHeight);
  }
  features.push('left=' + left);
  features.push('top=' + right);
  features.push('scrollbars=1');

  var newWindow = window.open(url, title, features.join(','));

  if (window.focus) {
    newWindow.focus();
  }

  return newWindow;
}

Answer 10

（发布于2020年）

CrazyTim's answer的扩展名

您还可以将宽度设置为动态尺寸的百分比（或比率）。绝对大小仍然可以接受。

function popupWindow(url, title, w='75%', h='16:9', opts){
    // sort options
    let options = [];
    if(typeof opts === 'object'){
        Object.keys(opts).forEach(function(value, key){
            if(value === true){value = 'yes';}else if(value === false){value = 'no';}
            options.push(`${key}=${value}`);
        });
        if(options.length){options = ','+options.join(',');}
        else{options = '';}
    }else if(Array.isArray(opts)){
        options = ','+opts.join(',');
    }else if(typeof opts === 'string'){
        options = ','+opts;
    }else{options = '';}

    // add most vars to local object (to shorten names)
    let size = {w: w, h: h};
    let win = {w: {i: window.top.innerWidth, o: window.top.outerWidth}, h: {i: window.top.innerHeight, o: window.top.outerHeight}, x: window.top.screenX || window.top.screenLeft, y: window.top.screenY || window.top.screenTop}

    // set window size if percent
    if(typeof size.w === 'string' && size.w.endsWith('%')){size.w = Number(size.w.replace(/%$/, ''))*win.w.o/100;}
    if(typeof size.h === 'string' && size.h.endsWith('%')){size.h = Number(size.h.replace(/%$/, ''))*win.h.o/100;}

    // set window size if ratio
    if(typeof size.w === 'string' && size.w.includes(':')){
        size.w = size.w.split(':', 2);
        if(win.w.o < win.h.o){
            // if height is bigger than width, reverse ratio
            size.w = Number(size.h)*Number(size.w[1])/Number(size.w[0]);
        }else{size.w = Number(size.h)*Number(size.w[0])/Number(size.w[1]);}
    }
    if(typeof size.h === 'string' && size.h.includes(':')){
        size.h = size.h.split(':', 2);
        if(win.w.o < win.h.o){
            // if height is bigger than width, reverse ratio
            size.h = Number(size.w)*Number(size.h[0])/Number(size.h[1]);
        }else{size.h = Number(size.w)*Number(size.h[1])/Number(size.h[0]);}
    }

    // force window size to type number
    if(typeof size.w === 'string'){size.w = Number(size.w);}
    if(typeof size.h === 'string'){size.h = Number(size.h);}

    // keep popup window within padding of window size
    if(size.w > win.w.i-50){size.w = win.w.i-50;}
    if(size.h > win.h.i-50){size.h = win.h.i-50;}

    // do math
    const x = win.w.o / 2 + win.x - (size.w / 2);
    const y = win.h.o / 2 + win.y - (size.h / 2);
    return window.open(url, title, `width=${size.w},height=${size.h},left=${x},top=${y}${options}`);
}

用法：

// width and height are optional (defaults: width = '75%' height = '16:9')
popupWindow('https://www.google.com', 'Title', '75%', '16:9', {/* options (optional) */});

// options can be an object, array, or string

// example: object (only in object, true/false get replaced with 'yes'/'no')
const options = {scrollbars: false, resizable: true};

// example: array
const options = ['scrollbars=no', 'resizable=yes'];

// example: string (same as window.open() string)
const options = 'scrollbars=no,resizable=yes';

Answer 11

以上是上述解决方案的替代版本......

function openPopupCenter(url, title, w, h) {
  // Fixes dual-screen position
  // Most browsers use window.screenLeft
  // Firefox uses screen.left
  var dualScreenLeft = getFirstNumber(window.screenLeft, screen.left),
    dualScreenTop = getFirstNumber(window.screenTop, screen.top),
    width = getFirstNumber(window.innerWidth, document.documentElement.clientWidth, screen.width),
    height = getFirstNumber(window.innerHeight, document.documentElement.clientHeight, screen.height),
    left = ((width / 2) - (w / 2)) + dualScreenLeft,
    top = ((height / 2) - (h / 2)) + dualScreenTop,
    newWindow = window.open(url, title, getSpecs());

  // Puts focus on the newWindow
  if (window.focus) {
    newWindow.focus();
  }

  return newWindow;

  function getSpecs() {
    return 'scrollbars=yes, width=' + w + ', height=' + h + ', top=' + top + ', left=' + left;
  }

  function getFirstNumber() {
    for(var i = 0, len = arguments.length; i < len; i++) {
      var value = arguments[i];

      if (typeof value === 'number') {
        return value;
      }
    }
  }
}

Answer 12

我的ES6 JavaScript版本。
通过双屏设置在Chrome和Chromium上运行良好。

function openCenteredWindow({url, width, height}) {
    const pos = {
        x: (screen.width / 2) - (width / 2),
        y: (screen.height/2) - (height / 2)
    };

    const features = `width=${width} height=${height} left=${pos.x} top=${pos.y}`;

    return window.open(url, '_blank', features);
}

示例

openCenteredWindow({
    url: 'https://stackoverflow.com/', 
    width: 500, 
    height: 600
}).focus();

Answer 13

基于Facebook，但是使用媒体查询而不是用户代理正则表达式来计算是否有足够的空间（有一定的空间）用于弹出窗口，否则将全屏显示。手机上的Tbh弹出窗口仍会以新标签页打开。

function popupCenter(url, title, w, h) {
  const hasSpace = window.matchMedia(`(min-width: ${w + 20}px) and (min-height: ${h + 20}px)`).matches;
  const isDef = v => typeof v !== 'undefined';
  const screenX = isDef(window.screenX) ? window.screenX : window.screenLeft;
  const screenY = isDef(window.screenY) ? window.screenY : window.screenTop;
  const outerWidth = isDef(window.outerWidth) ? window.outerWidth : document.documentElement.clientWidth;
  const outerHeight = isDef(window.outerHeight) ? window.outerHeight : document.documentElement.clientHeight - 22;
  const targetWidth = hasSpace ? w : null;
  const targetHeight = hasSpace ? h : null;
  const V = screenX < 0 ? window.screen.width + screenX : screenX;
  const left = parseInt(V + (outerWidth - targetWidth) / 2, 10);
  const right = parseInt(screenY + (outerHeight - targetHeight) / 2.5, 10);
  const features = [];

  if (targetWidth !== null) {
    features.push(`width=${targetWidth}`);
  }

  if (targetHeight !== null) {
    features.push(`height=${targetHeight}`);
  }

  features.push(`left=${left}`);
  features.push(`top=${right}`);
  features.push('scrollbars=1');

  const newWindow = window.open(url, title, features.join(','));

  if (window.focus) {
    newWindow.focus();
  }

  return newWindow;
}

Answer 14

此混合解决方案在单屏和双屏设置中都对我有用

function popupCenter (url, title, w, h) {
    // Fixes dual-screen position                              Most browsers      Firefox
    const dualScreenLeft = window.screenLeft !== undefined ? window.screenLeft : window.screenX;
    const dualScreenTop = window.screenTop !== undefined ? window.screenTop : window.screenY;
    const left = (window.screen.width/2)-(w/2) + dualScreenLeft;
    const top = (window.screen.height/2)-(h/2) + dualScreenTop;
    return window.open(url, title, 'toolbar=no, location=no, directories=no, status=no, menubar=no, scrollbars=no, resizable=no, copyhistory=no, width='+w+', height='+h+', top='+top+', left='+left);
}

Answer 15

我在外接显示器的弹出窗口居中时遇到问题，并且 window.screenX 和 window.screenY 分别为负值（-1920，-1200）。我已经尝试了以上所有建议的解决方案，并且它们在主显示器中都运行良好。我想离开

左右边缘留有200 px
顶部和底部的边距为150像素

这对我有用：

 function createPopupWindow(url) {
    var height = screen.height;
    var width = screen.width;
    var left, top, win;

    if (width > 1050) {
        width = width - 200;
    } else {
        width = 850;
    }

    if (height > 850) {
        height = height - 150;
    } else {
        height = 700;
    }

    if (window.screenX < 0) {
        left = (window.screenX - width) / 2;
    } else {
        left = (screen.width - width) / 2;
    }

    if (window.screenY < 0) {
        top = (window.screenY + height) / 4;
    } else {
        top = (screen.height - height) / 4;
    }

    win=window.open( url,"myTarget", "width="+width+", height="+height+",left="+left+",top="+top+"menubar=no, status=no, location=no, resizable=yes, scrollbars=yes");
    if (win.focus) {
        win.focus();
    }
}

Answer 16

这将根据您的屏幕尺寸进行计算

<html>
<body>
<button onclick="openfunc()">Click here to open window at center</button>
<script>
function openfunc() {
windowWidth = 800;
windowHeight = 720;
 var left = (screen.width - windowWidth) / 2;
            var top = (screen.height - windowHeight) / 4;
            var myWindow = window.open("https://www.google.com",'_blank','width=' + windowWidth + ', height=' + windowHeight + ', top=' + top + ', left=' + left);
}
</script>
</body>
</html>

Answer 17

除非浏览器占据全屏，否则接受的解决方案不起作用，

这似乎总是有效

  const popupCenterScreen = (url, title, w, h, focus) => {
    const top = (screen.height - h) / 4, left = (screen.width - w) / 2;
    const popup = window.open(url, title, `scrollbars=yes,width=${w},height=${h},top=${top},left=${left}`);
    if (focus === true && window.focus) popup.focus();
    return popup;
  }

实现：

some.function.call({data: ''})
    .then(result =>
     popupCenterScreen(
         result.data.url,
         result.data.title, 
         result.data.width, 
         result.data.height, 
         true));

Answer 18

.center{
    left: 50%;
    max-width: 350px;
    padding: 15px;
    text-align:center;
    position: relative;
    transform: translateX(-50%);
    -moz-transform: translateX(-50%);
    -webkit-transform: translateX(-50%);
    -ms-transform: translateX(-50%);
    -o-transform: translateX(-50%);   
}

在屏幕上居中显示一个弹出窗口？

18 个答案: