找到了一条命名路线，但匹配失败

Question

我对cakephp 3和命名路线有一个奇怪的问题。

  foreach ($categoryProducts as $key => $categoryProduct) {

    /**
     * WORK
     * Result : http://www.website.com/shop/slugshop/products/slugcategory
     */
    $categoryProduct->href_shop_view = Router::url([
      'slug' => $shop->slug,
      'category' => 'some_caractere'.$categoryProduct->slug,
       '_name' => 'viewShopProductsByCategory'
     ]);

    /**
     * Dont't work
     * Result : A named route was found for "viewShopProductsByCategory", but matching failed. 
     */
    $categoryProduct->href_shop_view = Router::url([
      'slug' => $shop->slug,
      'category' => $categoryProduct->slug,
      '_name' => 'viewShopProductsByCategory'
    ]);

  }

在我的routes.php中

Router::connect('/shop/:slug/products/:category',
     ['controller' => 'shops','action' => 'products'],
     ['slug'=>'[^\/]+','category'=>'[^\/]+','pass'=>['slug','category'],'_name' => 'viewShopProductsByCategory'
   ]
);

你能帮助我吗，因为我还没有找到解决方案而且我不理解我的错误......

感谢您的帮助

修改1

@ndm就像你可以看到我使用相同的命名路线，同一个商店slug和类别slug。

但是，如果 $ categoryProduct-＆gt; slug ，如果你没有在之前添加somme caractere，则会返回任何内容

修改2

debug($categoryProduct->slug); // Return "e-cigarette"
debug($shopp->slug); // Return "vapoton-com"

如果我直接写：

$categoryProduct->href_shop_view = Router::url([
  'slug' => 'vapoton-com',
  'category' => 'e-cigarette',
   '_name' => 'viewShopProductsByCategory'
 ]);

这是工作！

感谢您的帮助