如果子div不包含<a> tag?

时间:2016-11-21 15:36:29

标签: jquery

I'm trying to hide a parent div (i.e., #post) if the child div (i.e., .post-title) doesn't contain an <a> tag. Any insight in how to accomplish this correctly with the code I've modified?

<div id="latest">
    <div id="post">
        <div class="post-image post-image-1"></div>
        <div id="post-content">
            <div class="post-title post-title-1"></div>
            <div id="post-date"></div>
        </div>
    </div>
<div id="post">
        <div class="post-image post-image-2"></div>
        <div id="post-content">
            <div class="post-title post-title-2"></div>
            <div id="post-date"></div>
        </div>
    </div>
</div>
$('.post-title').not($('a').hide($("#post"));

4 个答案:

答案 0 :(得分:5)

  

注意:复制id是犯罪行为。

通过将所有id对等方式更改为class来实现正确,这应该有效:

&#13;
&#13;
$(function () {
  $(".post-title").filter(function () {
    return $(this).find("a").length == 0;
  }).hide();
});
&#13;
<script src="https://code.jquery.com/jquery-3.0.0.js"></script>
<div id="latest">
  <div class="post">
    <div class="post-image post-image-1"></div>
    <div class="post-content">
      <div class="post-title post-title-1">Hide This</div>
      <div class="post-date"></div>
    </div>
  </div>
  <div class="post">
    <div class="post-image post-image-2"></div>
    <div class="post-content">
      <div class="post-title post-title-2"><a href="">Don't Hide</a></div>
      <div class="post-date"></div>
    </div>
  </div>
</div>
&#13;
&#13;
&#13;

答案 1 :(得分:1)

首先:多次使用ID。每个ID都应该是唯一的:)

其次:$('.post').not( ':has(".post-title a")' ).addClass('hide')

答案 2 :(得分:1)

您可以简单地使用jQuery&#39; .filter

像这样:

{
    "@rid": "#1:0",
    "property": "ValueForA",
    "connected": "[#2:0, #2:1]"
}

见下面的例子

&#13;
&#13;
$('.post-title').filter(function(i) { return !$(this).find('a').length }).hide();
&#13;
$('.post-title').filter(function(i) { return !$(this).find('a').length }).hide();
&#13;
&#13;
&#13;

答案 3 :(得分:0)

只需使用jQuery的toggle使用布尔值来检查子项的长度:

/* Loop Through Parents */
$('#post').each(function() {
    $(this).toggle($(this).children('a').length > 0);
});
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