Question

我有一个列出order_id，order_date和user_id的表。

我没有问题检索每个客户订单的数量，并在order_id旁边显示。但是，我一直尝试失败的是在每个order_id旁边显示每个客户的第n个订单值。

SELECT order.id,
       order.user_id,
       date(from_unixtime(order.created_date))
       COUNT(order2.id)
FROM order order
JOIN order order2
           ON order2.user_id = order.user_id
AND order2.created_date <= order.created_date
GROUP
BY order.user_id,
   date(from_unixtime(order.created_date)),
   order.id
ORDER
BY order.user_id,
   date(from_unixtime(order.created_date)),
   order.id;

这只给出了每个订单的每个订单的订单总数，而不是第n个值。

结果应该是这样的：

created_date  order_id  user_id  order_number
2016-11-21     234        12       2
2016-10-15     123        16       1
2016-10-03     234        12       1

提前多多感谢！

Answer 1

好吧，你可以添加另一个连接并稍后更改第一个：

SELECT order.id,
       order.user_id,
       date(from_unixtime(order.created_date))
       COUNT(distinct order3.id) - COUNT(distinct order2.id)
FROM order order
JOIN order order2
           ON order2.user_id = order.user_id
AND order2.created_date > order.created_date
JOIN order order3
           ON order2.user_id = order.user_id
GROUP
BY order.user_id,
   date(from_unixtime(order.created_date)),
   order.id
ORDER
BY order.user_id,
   date(from_unixtime(order.created_date)),
   order.id;

Mysql：显示每个订单的每个客户的订单号

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