用户未存储在数据库Spring中

时间:2016-11-27 18:20:59

标签: spring jdbc spring-security

我在Spring上用安全性编写应用程序。我与用户建立了数据库,我可以在数据库中以用户身份登录应用程序。但是,当我尝试在DB中注册新用户时,它不会存储。

  

我没有错误,只是重定向到主页。

如果我取消注释自动登录字符串,我会得到Null Point EX。

这是我的应用程序的结构:

enter image description here

UserServiceImpl.class:

componentWillMount

控制器方法:

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Service; 
import java.util.HashSet;
import java.util.Set;

import com.ya.pokupay.dao.RoleDAO;
import com.ya.pokupay.dao.UserDAO;
import com.ya.pokupay.model.Role;
import com.ya.pokupay.model.User;
import org.springframework.security.crypto.bcrypt.BCryptPasswordEncoder;

@Service
public class UserServiceImpl implements UserService {

    @Autowired
    private UserDAO userDao;

    @Autowired
    private RoleDAO roleDao;

    @Override
    public void save(User user) {
        System.out.println("HERE");
        Set<Role> roles = new HashSet<>();
        roles.add(roleDao.getOne(1L));
        user.setRoles(roles);
        System.out.println("user: " + user);
        userDao.save(user);
    }

    @Override
    public User findByUsername(String username) {
        return userDao.findByUsername(username);
    }
}

UserDetailServiceImpl:

@RequestMapping(value = "/registration", method = RequestMethod.POST)
    public String registration(@ModelAttribute("userForm") User userForm, BindingResult bindingResult, Model model) {
        userValidator.validate(userForm, bindingResult);

        if (bindingResult.hasErrors()) {
            return "registration";
        }

        userService.save(userForm);

        //securityService.autoLogin(userForm.getUsername(), userForm.getConfirmPassword());

        return "redirect:/all";
    }

如果可以帮助我可以添加更多代码或设置。

编辑:

UserDAO的:

import com.ya.pokupay.dao.UserDAO;
import com.ya.pokupay.model.Role;
import com.ya.pokupay.model.User;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.security.core.GrantedAuthority;
import org.springframework.security.core.authority.SimpleGrantedAuthority;
import org.springframework.security.core.userdetails.UserDetails;
import org.springframework.security.core.userdetails.UserDetailsService;
import org.springframework.security.core.userdetails.UsernameNotFoundException;
import org.springframework.transaction.annotation.Transactional;

import java.util.HashSet;
import java.util.Set;

public class UserDetailsServiceImpl implements UserDetailsService{

    @Autowired
    private UserDAO userDao;

    @Override
    @Transactional(readOnly = true)
    public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
        User user = userDao.findByUsername(username);

        Set<GrantedAuthority> grantedAuthorities = new HashSet<>();

        for (Role role : user.getRoles()) {        
            grantedAuthorities.add(new SimpleGrantedAuthority(role.getName()));
        }
        return new org.springframework.security.core.userdetails.User(user.getUsername(), user.getPassword(), grantedAuthorities);
    }
}

1 个答案:

答案 0 :(得分:0)

我没有找到解决方案,所以我只编写了自己的asve方法实现,它对我有用。

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