Question

chrome检查时文件为空。所有其他页面都可以正常工作并显示基本表单。从未遇到过这样的错误。放入html时，表单本身就有效，但我无法与SQL DB正常通信。可以提供任何帮助。

<?php 

//Connects to your Database 
$conect = mysqli_connect("db location","username","password", "forks") or die(mysql_error()); 

//Checks if there is a login cookie
if(isset($_COOKIE['ID_your_site'])){ //if there is, it logs you in and directes you to the members page
    $username = $_COOKIE['ID_your_site']; 
    $pass = $_COOKIE['Key_your_site'];
    $check = mysqli_query($conect, "SELECT * FROM users WHERE username = '$username'")or die(mysql_error());

    while($info = mysqli_fetch_array( $check )){
        if ($pass != $info['password']){}
        else{
            header("Location: login.php");
        }
    }
 }

 //if the login form is submitted 
 if (isset($_POST['submit'])) {

    // makes sure they filled it in
    if(!$_POST['username']){
        die('You did not fill in a username.');
    }
    if(!$_POST['pass']){
        die('You did not fill in a password.');
    }

    // checks it against the database
    if (!get_magic_quotes_gpc()){
        $_POST['email'] = addslashes($_POST['email']);
    }

    $check = mysqli_query($conect, "SELECT * FROM users WHERE username = '".$_POST['username']."'")or die(mysql_error());

 //Gives error if user dosen't exist
 $check2 = mysqli_num_rows($check);
 if ($check2 == 0){
    die('That user does not exist in our database.<br /><br />If you think this is wrong <a href="login.php">try again</a>.');
}

while($info = mysqli_fetch_array( $check )){
    $_POST['pass'] = stripslashes($_POST['pass']);
    $info['password'] = stripslashes($info['password']);
    $_POST['pass'] = md5($_POST['pass']);

    //gives error if the password is wrong
    if ($_POST['pass'] != $info['password']){
        die('Incorrect password, please <a href="login.php">try again</a>.');
    }

    else{ // if login is ok then we add a cookie 
        $_POST['username'] = stripslashes($_POST['username']); 
        $hour = time() + 3600; 
        setcookie(ID_your_site, $_POST['username'], $hour); 
        setcookie(Key_your_site, $_POST['pass'], $hour);     

        //then redirect them to the members area 
        header("Location: members.php"); 
    }
}
}
else{
// if they are not logged in 
?>

 <form action="<?php echo $_SERVER['PHP_SELF']?>" method="post"> 

 <table border="0"> 

 <tr><td colspan=2><h1>Login</h1></td></tr> 

 <tr><td>Username:</td><td> 

 <input type="text" name="username" maxlength="40"> 

 </td></tr> 

 <tr><td>Password:</td><td> 

 <input type="password" name="pass" maxlength="50"> 

 </td></tr> 

 <tr><td colspan="2" align="right"> 

 <input type="submit" name="submit" value="Login"> 

 </td></tr> 

 </table> 

 </form> 

 <?php 
 }
 ?>

正如您所看到的，表单是一个没有格式的通用html表单，因为我打算将其保留，直到一切正常。

Answer 1

而不是：

$conect = mysqli_connect("db location","username","password", "forks") or die(mysql_error());

试试这个：

$conect = new mysqli("db location","username","password", "forks");
if ($conect->connect_error) {
    die('Connect Error (' . $conect->connect_errno . ') '
            . $conect->connect_error);
}

如果它不起作用，请告诉我它会抛出什么错误。

Answer 2

试试这个

$check = mysqli_query($conect, "SELECT * FROM users WHERE username = '".$username."'") or die(mysqli_error($conect));

而不是这个

$check = mysqli_query($conect, "SELECT * FROM users WHERE username = '$username'")or die(mysql_error());

PHP页面不会加载

2 个答案: