Question

我从数据库返回的users对象如下所示：

[
    {
        "id":1,
        "name":"Bob",
        "category":"admin",
        "email":"test1@test.com",
        "phone":"123456789",
        "gender":"male",
    },
    {
        "id":2,
        "name":"John",
        "category":"user",
        "email":"john@test.com",
        "phone":"123456789",
        "gender":"male",
    },
    {
        "id":3,
        "name":"Jane",
        "category":"admin",
        "email":"jane@test.com",
        "phone":"123456789",
        "gender":"female",
    },
]

现在，我想遍历所有users对象并删除category属性为user的所有用户，以便生成的users对象仅保留{{1类别。

我想用foreach循环来做这件事。请问我该如何解决这个问题？或者我有什么更好的方法来实现这个目标？

Answer 1

假设数组是json格式，一行代码：

$users = array_filter(json_decode($users), function($user) {
    return $user->category != 'user';
});

如果它已经是一个有效的php数组，只需删除json_decode()

Answer 2

我猜这个数组是JSON格式的吗？无论如何..我修复了你的无效JSON，所以你应该能够看到它是如何完成的。

$json = '

[{
    "id": 1,
    "name": "Bob",
    "category": "admin",
    "email": "test1@test.com",
    "phone": "123456789",
    "gender": "male"
}, {
    "id": 2,
    "name": "John",
    "category": "user",
    "email": "john@test.com",
    "phone": "123456789",
    "gender": "male"
}, {
    "id": 3,
    "name": "Jane",
    "category": "admin",
    "email": "jane@test.com",
    "phone": "123456789",
    "gender": "female"
}]

';

$array = json_decode($json, true); //Fixed and converted JSON into PHP Assoc Array 

foreach($array as $k=>$v) { 
    foreach ($array[$k] as $key=>$value) { 
      if ($key === "category" && $value === "user") { //If Value of 2D is equal to user and cat

          unset($array[$k]); //Delete from Array 
      }
    }  
}

var_dump($array); //Output Array

<强>输出

array(2) {
    [0] => array(6) {
        ["id"] => int(1)["name"] => string(3)
        "Bob" ["category"] => string(5)
        "admin" ["email"] => string(14)
        "test1@test.com" ["phone"] => string(9)
        "123456789" ["gender"] => string(4)
        "male"
    }[2] => array(6) {
        ["id"] => int(3)["name"] => string(4)
        "Jane" ["category"] => string(5)
        "admin" ["email"] => string(13)
        "jane@test.com" ["phone"] => string(9)
        "123456789" ["gender"] => string(6)
        "female"
    }
}

修改的

*正如@sevavietl在评论中指出的那样，如果数组的任何其他元素被称为user，那么这将被删除。我已经将代码更改为现在测试密钥（类别）以及值。 *

Answer 3

您的输入看起来像JSON，因此您可以使用json_decode函数将其设为数组，您可以foreach，并且可以对其进行编码（json_encode）如果你想要相同的输出，请回到JSON。

<强>解决方案

以下代码应该对您有用：

<?php
// $json = output from your db
$json_output = json_decode($json, true);

foreach ($json_output as $user) {
    if ($user['category'] == 'admin') { // or it may be $user['category'] != 'user'
        $user_output[] = $user;
    }
}
print_r($user_output);
print_r(json_encode($user_output, true)); // if you want json output    
?>

<强> SQL

您还可以添加SQL查询WHERE语句。它可能如下所示：

SELECT * FROM users WHERE category = 'admin'

当然查询取决于您在表中的名称。有关SELECT查询的更多信息，请参阅以下手册。

<强>手册

有关您可以阅读的使用方法的更多信息：

在线编译

您可以查看其工作原理here

Answer 4

如果您只想删除“user”类别，则只需获取密钥并为删除该类别创建条件，并将类别“admin”放在该新阵列上。看看这个：

$json = '
[{
    "id": 1,
    "name": "Bob",
    "category": "admin",
    "email": "test1@test.com",
    "phone": "123456789",
    "gender": "male"
}, {
    "id": 2,
    "name": "John",
    "category": "user",
    "email": "john@test.com",
    "phone": "123456789",
    "gender": "male"
}, {
    "id": 3,
    "name": "Jane",
    "category": "admin",
    "email": "jane@test.com",
    "phone": "123456789",
    "gender": "female"
}]';

$arr = json_decode($json, true);

$newArr = array();
foreach($arr as $key => $value) {
    if($value["category"] == "admin") {
        $newArr[] = $value;
    }
}

echo '<pre>';
    print_r($newArr);
echo '</pre>';

如何从foreach循环php中的对象数组中删除对象

4 个答案: