如何加快此SQL查询?

时间:2010-11-03 13:44:49

标签: sql postgresql indexing clustered-index

我是SQL的新手,我正在尝试研究如何在postgres中加速复杂的SQL查询,也许是通过改进我对索引的使用。这是查询:

SELECT
    (SELECT ev.code FROM classification_item ci, enumeration_value ev
        WHERE ev.key_id = :ak_0
        AND ci.entry_id = t.id AND ci.value_id = ev.id) AS axis_0,
    (SELECT ev.code FROM classification_item ci, enumeration_value ev
        WHERE ev.key_id = :ak_1
        AND ci.entry_id = t.id AND ci.value_id = ev.id) AS axis_1,
    SUM(t.amount) as amount,
    (SELECT ev.code FROM classification_item ci, enumeration_value ev
        WHERE ev.key_id = :key_time_id
        AND ci.entry_id = t.id AND ci.value_id = ev.id) AS time
FROM "entry" t
WHERE t.dataset_id = :dataset_id
AND t.id IN (SELECT ci.entry_id FROM classification_item ci, enumeration_value ev
    WHERE ev.key_id = :k_0
    AND ev.code = :v_0 AND ci.value_id = ev.id)
GROUP BY time, axis_0, axis_1

这基本上是数据库模式(在Pylons中定义):

table_dataset = Table('dataset', meta.metadata,
    Column('id', Integer, primary_key=True),
    )
table_entry = Table('entry', meta.metadata,
    Column('id', Integer, primary_key=True),
    Column('dataset_id', Integer, ForeignKey('dataset.id')),
    Column('amount', Float()),
    )
table_classification_item = Table('classification_item', meta.metadata,
    Column('id', Integer, primary_key=True),
    Column('entry_id', Integer, ForeignKey('entry.id'), index=True),
    Column('value_id', Integer, ForeignKey('enumeration_value.id'), index=True)
)
table_enumeration_value = Table('enumeration_value', meta.metadata,
    Column('id', Integer, primary_key=True),
    Column('key_id', Integer, ForeignKey('key.id'), index=True),
    Column('code', UnicodeText(), index=True),
    )

它的索引如下:

"dataset_pkey" PRIMARY KEY, btree (id)
"entry_pkey" PRIMARY KEY, btree (id)
"classification_item_pkey" PRIMARY KEY, btree (id)
"ix_classification_item_entry_id" btree (entry_id)
"ix_classification_item_value_id" btree (value_id)
"enumeration_value_pkey" PRIMARY KEY, btree (id)
"ix_enumeration_value_code" btree (code)
"ix_enumeration_value_key_id" btree (key_id)

我是否遗漏了任何可以加速查询的明显索引?特别是:

  • 我应该使用'聚集'索引吗?
  • 我是否也应该在amount上为entry建立索引,或者对SUM(t.amount) as amount没有区别?

感谢您的帮助。我知道这是一个非常复杂的问题,所以请告诉我是否可以采取任何措施来改进它。

------更新--------------

上述查询的

The output from EXPLAIN ANALYZE

2 个答案:

答案 0 :(得分:1)

如果enumeration_value表很小,我猜你可以通过将axis_1axis_0作为连接来获得一些改进,并添加一个额外的索引。

类似的东西(未经测试)

CREATE INDEX idx_ci_vi_ei ON classification_item(value_id, entry_id);

CREATE INDEX idx_id_ki ON enumeration_value(id, key_id);

SELECT
    ci_0.code AS axis_0,
    ci_1.code AS axis_1,
    SUM(t.amount) as amount,
    ci_t.code AS time
FROM 
   "entry" t,
   (SELECT ev.code FROM classification_item ci, enumeration_value ev
        WHERE ev.key_id = :ak_0 AND ci.value_id = ev.id) ci_0,
   (SELECT ev.code FROM classification_item ci, enumeration_value ev
        WHERE ev.key_id = :ak_1 AND ci.value_id = ev.id) ci_1,
   (SELECT ev.code FROM classification_item ci, enumeration_value ev
        WHERE ev.key_id = :key_time_id AND ci.value_id = ev.id) ci_t
WHERE t.dataset_id = :dataset_id 
AND t.id IN (SELECT ci.entry_id FROM classification_item ci, enumeration_value ev
    WHERE ev.key_id = :k_0
    AND ev.code = :v_0 AND ci.value_id = ev.id)
AND t.id = ci_0.entry_id AND t.id = ci_1.entry_id AND t.id = ci_t.entry_id
GROUP BY time, axis_0, axis_1

答案 1 :(得分:0)

关于查询计划有什么EXPLAIN ANALYZE

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