警告:从不兼容的指针类型传递'find_middle_artist'的参数1

时间:2016-11-30 14:17:40

标签: c

所以,我正在制作一个程序,对具有三个值作为其成员的艺术家列表进行排序。但每次我编译,我都会得到标题错误。我正在施展,并且不明白为什么会发生这种情况。

struct artist *sort_artists(struct play *artistl, int criterion){

   if (!(criterion == PLAYCOUNT || criterion == ARTISTID)){
     printf("[ERROR]: Incorrect Criterion");
     return (struct artist *)artistl;
   }
   else{
     if (criterion == PLAYCOUNT){
      struct artist *m = NULL;
      struct artist *x = NULL;
      struct artist *y = NULL;
      if (artistl == NULL || artistl->next == NULL)
        return (struct artist *)artistl;

      x = (struct artist *)artistl;
      m = find_middle_artist((struct artist *)artistl);
      y = m;
      m->next = NULL;
      return merge(sort_artists(x, criterion), sort_artists(y, criterion));
    }
  else if (criterion == ARTISTID){
    struct artist *m = NULL;
    struct artist *x = NULL;
    struct artist *y = NULL;

    if (artistl == NULL || artistl->next == NULL)
      return (struct artist *)artistl;

    x = (struct artist *)artistl;
    m = find_middle_artist(artistl);
    y = m;
    m->next = NULL;
    return merge(sort_artists(x, criterion), sort_artists(y, criterion));
  }

} }

0 个答案:

没有答案